PR 2020 (Shading and Loops) Author
Posts: 668
Location: India | chaotic_iak - 2018-04-17 5:31 AM
My approach for Arrows 3 was slightly different but with the same conclusion. Sum of all numbers is 82. Corner arrows can point to up to 4 numbers, and middle arrows can point up to 3 numbers. The remaining off-corner arrows must therefore point to at least 3 numbers each (8x4 + 4x3 + 8x5 = 84, so we only have 2 to spare), so they must all go straight.
Interesting. Great to learn new approaches. Although I created with some particular idea, it turns out there are many other approaches to solve the same thing which even I am not aware of.
Thanks for sharing your approach. |