tamz29 - 2011-12-12 1:53 PM

In Neighbours=N, will the information of N=? be given?

swaroop2011 - 2011-12-12 6:07 PM

hey just to clarify the partial point system of LINKED MINI SUDOKU

it says "grid without hints 30,grid with hints 15 points each"

so if i solved four grids that has hints and one grid which does not have hints..
then i will get 15+15+15+15+30=90 points greater than 75(for completely solved puzzle)

Gotroch - 2011-12-12 7:59 PM

I guess there will be only four grids (30+15+15+15 = 75)

swaroop2011 - 2011-12-12 9:26 PM

in SERIES SUDOKU

in given series of numbers : the number 1 is repeated
is it purposefully given or bymistakely.

Rohan Rao - 2011-12-12 9:31 PM


The theme is 'Pi'.

David McNeill - 2011-12-13 3:54 AM

In Series Sudoku, is it true, from a solving point of view, that the order of the series has no significance and we simply have to ensure that the shaded cells contain a digit contained in the set of given numbers?

swaroop2011 - 2011-12-12 9:41 PM



hey sry i didnt understood what are u saying?

Fred76 - 2011-12-13 5:36 PM

It looks very interesting .

I find it difficult to distinguish the gray lines and arrows on hidden skyscrapers and diagonal consecutive. Could they be a bit darker on the test grids?

Thanks !

Fred

greenhorn - 2011-12-15 3:38 PM

I definitely love the "number tree." Great idea, Deb!

utkaarsh - 2011-12-15 9:07 PM

I was solving the IB exmaples and found Windoku sample a tough one, took more than 10 minutes, just wanted general opinion on its difficulty, if some top solvers can share thier timing !!

swaroop2011 - 2011-12-16 6:01 PM

can somebody help me out with NEIGHBOURS
i only got one number 5 at R8C8 and thats it..
No further clues to proceed accept some pencil markings..

Fred76 - 2011-12-16 6:42 PM



In the 9th box: you have a pair 28 next to the 5 (edges). Then at R9C7 in can only be 4 or 7. Then you can place the 1 in row 8 (considering that there isn't edge between R9C67, then 4 can't be placed at R9C6 ). You can place 1 and 4 in 8th box, then the 9 in row 8, etc...

I like how the N=3 works (I think that perhaps I'm the inventor of this variant?): You have to "think" digits into 3 groups: 1-4-7, 2-5-8 and 3-6-9. And in these groups 4, 5 and 6 play a central role.
Each N has it's own logic, perhaps you have to think about it for each N before the test

Fred