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Posts: 175
 
Location: India | |
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Posts: 175
Location: India | Indian Puzzle Championship 2013 will be held online on 7th July (Sunday)
Quick notes :
1) The championship will be online, will start at 2:00 PM on the specified day.
2) The format will be very similar to last year.
3) Best 3 performers will be invited to the Indian team representing at China in October. Like last year, with a strong performance at WPC, Amit Sowani receives a wild card for the Indian team. |
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Posts: 175
Location: India | For first timers
==========
If you are planning to participate for the first time and are curious about what types of puzzles to expect, here are some classic types that you will see in the championship along with many other variants
Sudoku
Skyscrapers
Slitherlink / Fence
Hitori / All Alone
Kakuro / Cross Sums
Battleships
Star Battle
Many of these puzzles appear in news papers, so that will be a good source of practice. But the championships puzzles will vary with respect to difficulty. It is always good idea to check the previous years' puzzles ( 2009, 2010, 2011, 2012) .
The Instructions Booklet with final puzzle types will be published around 5 days before the championship.
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Posts: 15
Location: India | Hi,
Please consider having IPC on a different date as The Brands' Sudoku C'ship will be held on 13-14 july in Bangkok.
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Location: India | Dates for IPC - 7th July
New dates for IPC - 7th July
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PR 2020 (Shading and Loops) Author
Posts: 668
Location: India | looking forward to it :) |
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Posts: 15
Location: India | Thanks Deb/Amit for rescheduling the date for IPC.
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Posts: 8
Location: India | how to register for ipc 2013.?
please help i am a new user |
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Posts: 123
Location: India | Hi,
Welcome to LMI 
There is no other process for participating in Indian Puzzle Championship (IPC), registering at LMI is sufficient to participate.
Please do not open any new threads for IPC 2013 related things, follow/post queries in this thread of IPC 2013.
Regards,
Ravi |
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Posts: 8
Location: India | how to register for ipc 2013 ? whether the test can also be taken offline ?
please help i am a new user .... |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | inventor - 2013-06-18 5:19 PM
how to register for ipc 2013 ? whether the test can also be taken offline ?
please help i am a new user ....
You're already registered for LMI, so there's nothing you have to do other than watch this topic for the Submission link, and then login (with this same "inventor" user name) and participate.. |
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Posts: 123
Location: India | inventor - 2013-06-18 5:19 PM
how to register for ipc 2013 ?
Hi,
Your question is already answered here. whether the test can also be taken offline ?
The contest is not conducted offline. It is conducted online which means you have to take print out of the puzzle booklet and enter the answers at the link provided.
Watch this thread for more information.
Regards,
Ravi |
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Posts: 8
Location: India | hello
when the ipc will start and what is the duration of the test ?
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Mean Minis (2020) Author
Posts: 774
Location: India | inventor - 2013-06-20 2:19 PM
when the ipc will start
This information is already given earlier in this thread - "2pm on the specified day"
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and what is the duration of the test ?
This will be announced soon. But since the format is similar to last year, it could be about 2.5 hours duration. |
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Typed Logic Author
Posts: 241
Location: Indonesia | By 2pm, in what timezone? (I think the answer is "Indian Standard Time" which Wikipedia says to be UTC+05.30 (aka the time is 08.30 am UTC), but just want to make sure.)
Also, I assume that this is not like other puzzle tests where you have a 48-hour window or something to start? (As in you must start at 2pm; if you're late, you lose the lost time?) |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | chaotic_iak - 2013-06-21 9:36 PM
By 2pm, in what timezone? (I think the answer is "Indian Standard Time" which Wikipedia says to be UTC+05.30 (aka the time is 08.30 am UTC), but just want to make sure.)
Also, I assume that this is not like other puzzle tests where you have a 48-hour window or something to start? (As in you must start at 2pm; if you're late, you lose the lost time?)
Usually (last year is an example, scroll down in the link provided above to see the unofficial Rest-of-the-world results), although the IPC is at a fixed time for all Indian participants, it is extended thereafter for international players to participate. Hopefully, the format is similar this year. |
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Location: India | hi
please help me for getting the solution of ipc 2010.
thanking you |
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Location: India | inventor - 2013-06-24 10:07 PM
hi
please help me for getting the solution of ipc 2010.
thanking you Please post specific puzzle for which you need solution. Making solutions for all puzzles will take time for us. |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | inventor - 2013-06-24 10:07 PM
hi
please help me for getting the solution of ipc 2010.
thanking you
Another way to go about it is, if you want to check your solutions from solving those puzzles, you can just post your solution images here, and we'll confirm if they are right or not. You can also post incomplete puzzles here if you are stuck and want us to tell you the next step in order to proceed. :) |
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Posts: 8
Location: India | hi
thanks for the reply.
i am post my problems here.
hoping for a favorable reply :)
Ipc 2009
Minesweeper:
I can’t understand the meaning of the last line “when all the four grids are solved single coordinate should exactly contain one mine”.
Dominos:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
No four in a row;
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
Is more than one answer possible??
Ripple effect :
Please check the last row of the answer it’s not following the question rule that if same digit appears then they should be separated by cells equal to the digit. {for 1}
Triangle count:
I got a max. 31 triangles on many attempts.
Is the answer given 32 correct?
Trid:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
Polygraph:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | inventor - 2013-06-26 7:07 PM
Ipc 2009
Minesweeper:
I can’t understand the meaning of the last line “when all the four grids are solved single coordinate should exactly contain one mine”.
I'll deal with your queries one at a time. If you see the example in the Instruction booklet, you will see the letters A-H, and in the competition puzzle, you will see 1-4 at the bottom and A-D on the side. This is basically an easy way to name the rows and columns. So, I'll explain using the competition puzzle. In each 4x4 grid, take the first row as "3" and 1st column as "A". So, the intersection of these will be one cell, the cell that is left-most in the 3rd row, and this cell can be called A3 for reference. So in all 4 grids, A3 can have a mine in at most just one grid. (below is an image showing A3 for 2 of the grids, you'll need to use this co-ordination for all 4)
 (2.png)
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 2.png (6KB - 2 downloads)
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | inventor - 2013-06-26 7:07 PM
Dominos:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
I usually use a few basic tricks, like say, search for some pair that has only one instance in the entire grid. In the competition puzzle, one of those pairs is 0-2 I think, so I've marked it.
That could be time consuming, so sometimes things can be found in the corners, like if there's something like
1 2 _ _
2 _ _ _
in a corner, you know that, whichever way the 1 is paired, it has to be paired with 2, so you can then divide all borders in the rest of the grid where 2 and 1 are next to each other.
In the particular competition puzzle of 2010, there's another little trick - Right at the top, if the 5 to the right of the 2 pairs up with the 3 below, then that results in another 3-5 pairing to the right of that, considering all numbers need to be paired (Rules say layout is showed with domino edges removed, so everything's part of a domino). So, the 5 pairs up with the 2.
I've also marked below a border above a 1 that I haven't explained. The explanation for that is, there's three 1s there, and that is the only place where 1-1 pairing can be done. So that 1 will be paired rightward or downward, so can't go upward/leftward, hence the line above it.
Domino's not one of my good types though, so I might have missed some key points. But once you start spotting these techniques you could tend to ease into whats needed to solve it.
 (Domino.png)
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Domino.png (51KB - 2 downloads)
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | inventor - 2013-06-26 7:07 PM
No four in a row;
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
Is more than one answer possible??
Firstly, unless explicitly mentioned otherwise, all puzzles have exactly one solution only. As for how to start, just look at 4 consecutive cells in a row/column/diagonal where 3 are already given and are all X (or all O). Then the 4th cell in that row/column/diagonal must be the other sign (Not the one given in all the other 3). If you start at these places, that forms other places where this happens and so on and you can go on solving like that and reach the single solution.
For the competition puzzle in 2009, see the 3rd row, there's an X in the 1st, 2nd and 4th cell. So, by the above explanation, the 3rd cell has to be O, else there'd be 4 Xs in a row. |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | inventor - 2013-06-26 7:07 PM
Ripple effect :
Please check the last row of the answer it’s not following the question rule that if same digit appears then they should be separated by cells equal to the digit. {for 1}
Triangle count:
I got a max. 31 triangles on many attempts.
Is the answer given 32 correct?
Trid:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
For the Ripple Effect - I don't get exactly what you mean. Do you mean that the 1s are touching diagonally? If so, they can be next to each other diagonally, the rule only states "same row or column". If you mean something else, is it possible to be clearer? (Maybe post a picture).
For Triangle Count - Given that multiple participants have participated in that Championship that year, if there is any problem, it'd already be reported mostly :) I'm guessing, you might have missed the hidden big triangle, pointing downwards? (There's one big traingle pointing upwards and one of that same size pointing downwards).
For Trid - Consider that digits can't repeat in any straight line. Now look at the competition puzzle, see the "6" sum. The only numbers that can come around it, due to no-repeat rule, are 1,2,3. Since the digit set is 1-6, the maximum sum that 2 adjacent cells can have is 11 (6+5), so the 14 next to the 6 has to have a 3 in the one circle they share, because otherwise, you need more than 11 in the other 2 cells which isn't possible. Use such things, and Sudoku-type eliminations along the straight lines, and you'll get there. |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1788
Location: India | inventor - 2013-06-26 7:07 PM
Polygraph:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
The easiest way to start the competition puzzle of 2009 is to use the 0. Think of it this way - Every cell has a total of 4 lines that can be around it. But no clue can have all 4 lines around it used, because that'll form a little square loop away from the main loop. So, a 0 has to be the number of lines used, rather than unused, because if 0 lines are unused, that means 4 lines are used. Therefore, all 0s have to be inside the loop and have no lines around them. Since the 0 is inside the loop, there needs to be some part of the loop "binding" it on all sides. so, you have a line in the last row, under the 0. This means, the 3 is "bound" as well and is also inside the loop, and there's your start, and you can now also prove that the two 1s are outside the loop and this means that 3 sides of theirs are used by the loop.
 (Polygraph.png)
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Polygraph.png (29KB - 0 downloads)
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