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Riad Khanmagomedov's April Contest — 3rd to 11th April 2015
   LMI Tests -> Annual Competitions64 posts • Page 1 of 3 • 1 2 3
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-06 12:18 PM (#18184 - in reply to #18181) (#18184) Top


Moscow Puzzle Cup 2016 Author

Posts: 234
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auroux - 2015-04-06 6:25 AM
In general, many of the answer keys seem trickier than necessary -- really, counting the C's? diagonals that go in the opposite of the usual direction? --, but it's too late to change them.

I'm a pronounced left-handed. Maybe because I offered unusual diagonals?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-06 7:44 PM (#18186 - in reply to #18034) (#18186) Top


Moscow Puzzle Cup 2016 Author

Posts: 234
10010020
Location: Russia
About puzzle 10 (APRIL CONTEST 2015 AT LMI):
It is not necessary for the line to start at cells with A and end at cells with I.
Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-06 10:18 PM (#18187 - in reply to #18034) (#18187) Top




Posts: 67
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Hello. New question : in Sudoku without wall, may a wall segment separate two cells of the same area ?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-06 11:37 PM (#18188 - in reply to #18187) (#18188) Top


Moscow Puzzle Cup 2016 Author

Posts: 234
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Puzlifouk - 2015-04-06 10:18 PM

Hello. New question : in Sudoku without wall, may a wall segment separate two cells of the same area ?

Hello, certainly not!
sliverbrain
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-07 10:04 AM (#18191 - in reply to #18034) (#18191) Top




Posts: 4

Location: India
#@!%^
Mihalich
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-07 11:40 AM (#18193 - in reply to #18034) (#18193) Top




Posts: 26
20
Location: Ukraine
????????????, ????! ??????? ?? ?????????? ???????.

4. ???????????? ??????.
????? ?????? ???????? ???????, ? ??????? ??? ??????, ????? ? ??????? ????????? ?????????? ? ???? ??? ? ?????? ?????.

1.????? ??, ??? ?????? ????? ? ??????? ?????? ???? ?? ??? ????????? ? ??????????????? ???????? ??? ??????? ?????????? ???? ? 2 ? 0, 2 ? 0 ? ?????????? ???????, ?? ?? ????????????. ????? ?? ? ???????????? ???? ???? 2 ? 5 - ??? ????????? "???????" ???????????
2. ????? ????? ?? ????? ???? ? ?????????? ?? ???????? ????????, 2 ? 5 ????? ??? ????

Zdravstvujte, Riad! Spasibo za interesnye zadanija.

4. ZAZERKAL''NYE SUDOKU.
Serym cvetom otmecheny zerkala, a zeljonym vse kletki, cifry v kotoryh zerkal'no otrazhajutsja v sebja ili v drugie cifry.

1.Verno li, chto kazhdaja cifra v zeljonoj kletke HOTJa BY RAZ otrzhaetsja v sootvetstvujushhej zeljonoj? Kak primere vnutrennie ugly s 2 i 0, 2 i 0 v zerkal'nyh zeljonyh, no ne povtorjajut'sja. Mogut li v edinstvennoj pare byt' 2 i 5 - jeto schitaetsja "zeljonym" otrazheniem?
2. Kakie cifry NE MOGUT BYT'' v zerkal'nyh NE ZELJoNYH? Naprimer, 2 i 5 mogut ili net?

Edited by Mihalich 2015-04-07 11:44 AM




(Mihalich_Post18193.png)



Attachments
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Attachments Mihalich_Post18193.png (17KB - 5 downloads)
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-07 2:00 PM (#18194 - in reply to #18193) (#18194) Top


Moscow Puzzle Cup 2016 Author

Posts: 234
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Location: Russia
Mihalich - 2015-04-07 11:40 AM
Zdravstvujte, Riad! Spasibo za interesnye zadanija.

4. ZAZERKAL''NYE SUDOKU.
Serym cvetom otmecheny zerkala, a zeljonym vse kletki, cifry v kotoryh zerkal'no otrazhajutsja v sebja ili v drugie cifry.

1.Verno li, chto kazhdaja cifra v zeljonoj kletke HOTJa BY RAZ otrzhaetsja v sootvetstvujushhej zeljonoj? Kak primere vnutrennie ugly s 2 i 0, 2 i 0 v zerkal'nyh zeljonyh, no ne povtorjajut'sja. Mogut li v edinstvennoj pare byt' 2 i 5 - jeto schitaetsja "zeljonym" otrazheniem?
2. Kakie cifry NE MOGUT BYT'' v zerkal'nyh NE ZELJoNYH? Naprimer, 2 i 5 mogut ili net?

Zdravstvujte, Vladimir!
1. Verno. Da, 2 i 5 mogut byt' v edinstvennoj pare (ne v diagonal'noj, razumeetsja).
2. Ogranichenij net: v belyh kletkah mogut vstretit'sja ljubye cifry, v tom chisle 2 i 5.
Mihalich
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-07 2:37 PM (#18195 - in reply to #18194) (#18195) Top




Posts: 26
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Vyhodit, 2 i 5 - jeto i zerkal'noe otrazhenie i net odnovremenno? ili tol'ko po gorizontali(vertikali)?

Mozhet li 2 byt' v zeljonoj kletke pri otrazhenii vpravo ili vniz ili tol'ko po diagonali?
3 mozhet byt' v zeljonoj kletke TOL''KO pri gorizontal'nom zerkale (vniz-vverh)?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-07 6:02 PM (#18198 - in reply to #18195) (#18198) Top


Moscow Puzzle Cup 2016 Author

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Mihalich - 2015-04-07 2:37 PM

Vyhodit, 2 i 5 - jeto i zerkal'noe otrazhenie i net odnovremenno? ili tol'ko po gorizontali(vertikali)?

Mozhet li 2 byt' v zeljonoj kletke pri otrazhenii vpravo ili vniz ili tol'ko po diagonali?
3 mozhet byt' v zeljonoj kletke TOL''KO pri gorizontal'nom zerkale (vniz-vverh)?

2 zerkal'no otrazhaetsja v 5, esli rech' o sosednih po gorizontali ili vertali poljah. V sebja 2 otrazhaetsja "tol'ko po diagonali".
S 3 vsjo verno.
Mihalich
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-07 9:01 PM (#18201 - in reply to #18034) (#18201) Top




Posts: 26
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4 ne mozhet byt' v zeljonoj kletke - neotrazimaja zerkal'no?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-07 9:57 PM (#18202 - in reply to #18201) (#18202) Top


Moscow Puzzle Cup 2016 Author

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Mihalich - 2015-04-07 9:01 PM

4 ne mozhet byt' v zeljonoj kletke - neotrazimaja zerkal'no?

Ne mozhet.
Yajendra
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-09 1:18 PM (#18212 - in reply to #18034) (#18212) Top





Posts: 18

Location: India
I am not able to solve even a single puzzle :(
rakesh_rai
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-09 1:31 PM (#18213 - in reply to #18212) (#18213) Top



Mean Minis (2020) Author

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Yajendra - 2015-04-09 1:18 PM

I am not able to solve even a single puzzle :(

Read the rules carefully, multiple times.
Try to find openings, applying the rules.
Try to think "If .... then what happens, is any rule violated."
And if you are stuck, save your work and come back later.


Eisbaer
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-09 5:11 PM (#18214 - in reply to #18034) (#18214) Top





Posts: 4

Location: The Netherlands
I have a little question about puzzle 10...
In the requested sentence there are two "I' 's and one time the digit 1. But it looks like there are three same characters "I" (or 1?) in the grid? Could all three characters be used for the digit 1?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-09 7:59 PM (#18215 - in reply to #18214) (#18215) Top


Moscow Puzzle Cup 2016 Author

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Eisbaer - 2015-04-09 5:11 PM

I have a little question about puzzle 10...
In the requested sentence there are two "I' 's and one time the digit 1. But it looks like there are three same characters "I" (or 1?) in the grid? Could all three characters be used for the digit 1?

1 can be any of the three "I". Two other "I" will be letters.
auroux
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-09 10:25 PM (#18216 - in reply to #18034) (#18216) Top


Hex Slitherlink Author

Posts: 145
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Just to make sure -- in "Tools", the answer key only describes whether the edges of the grid along the given row or column are occupied (and if so by what tool) or not, correct?

More precisely: what would be the answer key for the second row in the example? Am I right that it would be -----HH---- ? (i.e. the edges that are "inside" the ladder are unoccupied and so remain "-" in the answer key, even though there is a ladder) ?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-10 3:10 PM (#18218 - in reply to #18216) (#18218) Top


Moscow Puzzle Cup 2016 Author

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auroux - 2015-04-09 10:25 PM

Just to make sure -- in "Tools", the answer key only describes whether the edges of the grid along the given row or column are occupied (and if so by what tool) or not, correct?

More precisely: what would be the answer key for the second row in the example? Am I right that it would be -----HH---- ? (i.e. the edges that are "inside" the ladder are unoccupied and so remain "-" in the answer key, even though there is a ladder) ?

Yes, for the second row in the example the answer is recorded correctly.
kiwijam
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-11 8:19 AM (#18219 - in reply to #18034) (#18219) Top




Posts: 187
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Just a small confirmation for #10 (April Contest 2015 At LMI):
At the points of intersection, the line path must always continue straight ahead, it cannot have 2 turns (reflecting off each other)?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-11 11:35 AM (#18220 - in reply to #18219) (#18220) Top


Moscow Puzzle Cup 2016 Author

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kiwijam - 2015-04-11 8:19 AM

Just a small confirmation for #10 (April Contest 2015 At LMI):
At the points of intersection, the line path must always continue straight ahead, it cannot have 2 turns (reflecting off each other)?

The line path must always continue straight.
Mihalich
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-11 2:53 PM (#18221 - in reply to #18034) (#18221) Top




Posts: 26
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V zadanii 10 v forme dlja otvetov ukazyvaetsja na moju oshibku pri opisanii marshruta. Posle ukazanija poslednego ugla nichego ne nuzhno ukazyvat'? Ved' mozhet byt' nejasno napravlenie i dlina otrezka!
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-11 3:11 PM (#18222 - in reply to #18221) (#18222) Top


Moscow Puzzle Cup 2016 Author

Posts: 234
10010020
Location: Russia
Mihalich - 2015-04-11 2:53 PM

V zadanii 10 v forme dlja otvetov ukazyvaetsja na moju oshibku pri opisanii marshruta. Posle ukazanija poslednego ugla nichego ne nuzhno ukazyvat'? Ved' mozhet byt' nejasno napravlenie i dlina otrezka!

Ne nuzhno, ja dorisuju hvostik linii.
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-12 6:14 AM (#18223 - in reply to #18034) (#18223) Top


2000100050020
Location: India

Optimizer submissions


Link : http://logicmastersindia.com/lmitests/dl.asp?attachmentid=513

Like every year, we have prepared images for optimizer submissions. Couple of notes
1. In Puzzle 10 (LMI Contest 2015 at LMI) we had to manually determine the end point of the line in several cases. Please check if your submission is different than what is intended.
2. Riad is still solving all the Puzzle 12 (ROMAN COOL-L-L) submissions. If you notice any grid is invalid, please post here.

kiwijam
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-12 11:02 AM (#18224 - in reply to #18034) (#18224) Top




Posts: 187
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Location: New Zealand
Player3 grid has 8 solutions. It has six rows of "LOOLOOLOO", and 3 rows of "CLLCLLCL?", where "?" can be C or L.
debmohanty
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-12 11:07 AM (#18225 - in reply to #18224) (#18225) Top



1000500100100100202020
Location: India
Thanks James. What about Player13?
kiwijam
Subject: Re: Riad Khanmagomedov's April Contest — 3rd to 11th April 2015 @ 2015-04-12 2:31 PM (#18226 - in reply to #18034) (#18226) Top




Posts: 187
10020202020
Location: New Zealand
The Player13 grid is interesting.
The only way to get four adjacent 200s is with:
LOLOOLOOL
OOLLLOOLO
OLOOLLLOO
LOOLOOLOL
or its mirror image. (this is not simple to prove!)

So that fixes the top 4 rows, and if the bottom 4 are the same pattern then the solution must be:
LOLOOLOOL
OOLLLOOLO
OLOOLLLOO
LOOLOOLOL
LCLLCLLCL
LOLOOLOOL
OOLLLOOLO
OLOOLLLOO
LOOLOOLOL

If the mirror image option is used below then no solution is possible.

So the Player13 grid is fine.
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