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Riad Khanmagomedov's April Contest — 16th to 23nd April 2023
   LMI Tests -> Annual Competitions89 posts • Page 1 of 4 • 1 2 3 4
auroux
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-16 6:36 PM (#31458 - in reply to #31435) (#31458) Top


Hex Slitherlink Author

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For+puzzle+2%2c+the+answer+key+of+the+example+seems+wrong+(should+be+WWWIW).
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-16 11:13 PM (#31459 - in reply to #31435) (#31459) Top


2000100050020
Location: India
I confirm the other way: all double cells must have one half shaded and the other used.
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-16 11:16 PM (#31460 - in reply to #31435) (#31460) Top


2000100050020
Location: India
Auroux: You are right. The answer key for example 2 is wrong and there should be an I instead of an L.
Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-16 11:48 PM (#31461 - in reply to #31459) (#31461) Top




Posts: 67
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Location: France
OK! So that means half shaded cell may touch a shaded cell, at least diagonally!
In fact, my initial problem was that I inderstood ths conditions as :
- all double cells must have a shaded half and an unshaded half;
- all shaded cells and all shaded half of double cells do not touch.
But these two conditions cannot both be verified. If they were, this creates problem around the magenta and the lemon M.
So I have a new question: if a shaded half of a double celle can touch a shaded cell (or another shaded half of a double cell), is it necessarily diagonally, or can it also be orthogonally? Am I clear?
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 12:43 AM (#31462 - in reply to #31435) (#31462) Top


2000100050020
Location: India
Shaded cells cannot touch orthogonally. They can touch diagonally. (This is for puzzle 9)
Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 1:16 AM (#31463 - in reply to #31462) (#31463) Top




Posts: 67
202020
Location: France
Administrator - 2023-04-16 7:43 PM

Shaded cells cannot touch orthogonally. They can touch diagonally. (This is for puzzle 9)

OK Thanks. The puzzle booklet says something else ("The shaded cells do not touch, not even diagonally"). It will be corrected, I suppose ...
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 2:21 AM (#31464 - in reply to #31435) (#31464) Top


2000100050020
Location: India
Yes we will get it corrected soon.
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 11:32 AM (#31468 - in reply to #31435) (#31468) Top


2000100050020
Location: India

Potential Score Page

Link to Potential Score Page : https://logicmastersindia.com/2023/04Contest/score_potential.asp

Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 11:50 AM (#31469 - in reply to #31435) (#31469) Top




Posts: 67
202020
Location: France
Hello. New question about problem 10. What is the order of priority of the operations? Are the operations performed in the order they are found or do multiplication (X) and division (/) have priority? In other words, do we have 9-6/3=(9-6)/3=1 or 9-6/3=9-(6/3)=7?
prasanna16391
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 2:36 PM (#31470 - in reply to #31435) (#31470) Top


2021 World Sudoku+Puzzle Convention Organizer

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The rules say "without parenthesis" which means they are performed in the order they are found.
Barbitos
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 6:11 PM (#31472 - in reply to #31438) (#31472) Top




Posts: 6

Location: France
%5BQUOTE%5D8%2E+There+shall+be+no+online+solving+interface+%28like+penpa%29+provided+for+this+test%2E%5B%2FQUOTE%5D%0D%0A%0D%0AAre+we+still+allowed+to
E%5B%2FQUOTE%5D%0D%0A%0D%0AAre+we+still+allowed+to+use+penpa+to+copy+the+puzzles+and+solve+them+if+we%27re+more+confortable+with+it%3F%0D%0A%0D%0AAlso
e%27re+more+confortable+with+it%3F%0D%0A%0D%0AAlso%2C+to+what+extent+are+we+allowed+to+use+calculators+and+other+programs%3F+I%27m+guessing+the+line+i
rs+and+other+programs%3F+I%27m+guessing+the+line+is+drawn+at+something+like+%22only+what+you+could+do+on+windows%27+calculator+app%22+or+%22no+calcula
o+on+windows%27+calculator+app%22+or+%22no+calculators+allowed+period%22%0D%0A%0D%0AI+couldn%27t+find+any+clear+ruleset+for+this+contest%2C+if+there+a
d+any+clear+ruleset+for+this+contest%2C+if+there+are+i+would+like+to+know+where+it+is+%F0%9F%98%8A
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 6:19 PM (#31473 - in reply to #31469) (#31473) Top


Moscow Puzzle Cup 2016 Author

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Puzlifouk - 2023-04-17 11:50 AM

Hello. New question about problem 10. What is the order of priority of the operations? Are the operations performed in the order they are found or do multiplication (X) and division (/) have priority? In other words, do we have 9-6/3=(9-6)/3=1 or 9-6/3=9-(6/3)=7?

9-6/3=7. The priority of operations is standard.
prasanna16391
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 8:22 PM (#31474 - in reply to #31470) (#31474) Top


2021 World Sudoku+Puzzle Convention Organizer

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prasanna16391 - 2023-04-17 2:36 PM

The rules say "without parenthesis" which means they are performed in the order they are found.


Sorry, guess I was a bit wrong here, please follow what Riad says.
prasanna16391
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 8:24 PM (#31475 - in reply to #31472) (#31475) Top


2021 World Sudoku+Puzzle Convention Organizer

Posts: 1784
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Location: India
%5BQUOTE%5DBarbitos+%2D+2023%2D04%2D17++6%3A11+PM%0D%0A%0D%0AAre+we+still+allowed+to+use+penpa+to+copy+the+puzzles+and+solve+them+if+we%27re+more+conf
py+the+puzzles+and+solve+them+if+we%27re+more+confortable+with+it%3F%0D%0A%0D%0AAlso%2C+to+what+extent+are+we+allowed+to+use+calculators+and+other+pro
nt+are+we+allowed+to+use+calculators+and+other+programs%3F+I%27m+guessing+the+line+is+drawn+at+something+like+%22only+what+you+could+do+on+windows%27+
hing+like+%22only+what+you+could+do+on+windows%27+calculator+app%22+or+%22no+calculators+allowed+period%22%0D%0A%0D%0AI+couldn%27t+find+any+clear+rule
iod%22%0D%0A%0D%0AI+couldn%27t+find+any+clear+ruleset+for+this+contest%2C+if+there+are+i+would+like+to+know+where+it+is+%F0%9F%98%8A%5B%2FQUOTE%5D%0D%
to+know+where+it+is+%F0%9F%98%8A%5B%2FQUOTE%5D%0D%0A%0D%0ARedrawing+on+Penpa+is+fine%2E+There+is+no+rule+against+using+calculators+and+other+programs%
rule+against+using+calculators+and+other+programs%2C+but+the+contest+was+intended+to+be+done+without+them%2E+I+suppose+your+line+is+a+good+line+to+dra
+them%2E+I+suppose+your+line+is+a+good+line+to+draw%2E+
auroux
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 8:54 PM (#31477 - in reply to #31435) (#31477) Top


Hex Slitherlink Author

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On puzzle 10, does a circular equality loop "all around" with equal signs separating equal terms (in particular there must be at least two = signs), or do we get to "break the circle" where we want (not necessarily at an equality sign, and not necessarily in the same place in both directions) to form equalities that can be read clockwise or counterclockwise?

Concretely, if for some digits A,B,C,D,E one had the identities A_PLUS_BC=DEF and ED=CB_PLUS_AF, where the latter can be formed by writing the former around a circle, cutting in a different place, and reading in the other direction, would this be a valid solution ? Or is the only legal way to write the identity A_PLUS_BC=DEF to actually write "A_PLUS_BC=DEF=" around the circle (with an extra equal sign) and both expressions must be formed by cutting the circle at an "=" sign ?
auroux
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 8:59 PM (#31478 - in reply to #31435) (#31478) Top


Hex Slitherlink Author

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After more thinking, I assume the correct interpretation is that we can break the circle anywhere we want (not necessarily at an = sign, and not necessarily in the same place in both directions), and that the example I gave would be a valid solution. Otherwise, it would have been easier to state the problem as producing an equality which is valid when read forwards and backwards (no need to use a circle).
jeff10
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-17 9:26 PM (#31479 - in reply to #31435) (#31479) Top




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For the Bubbles Puzzle (Puzzle 2), do bubbles have to circle completely around an NxN (N=1,2,3) square of cells, or can a bubble of "size 3" only circle 3 of the leftmost cells while the center of the bubble is outside the grid?
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 12:06 AM (#31480 - in reply to #31477) (#31480) Top


Moscow Puzzle Cup 2016 Author

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auroux - 2023-04-17 8:54 PM

On puzzle 10, does a circular equality loop "all around" with equal signs separating equal terms (in particular there must be at least two = signs), or do we get to "break the circle" where we want (not necessarily at an equality sign, and not necessarily in the same place in both directions) to form equalities that can be read clockwise or counterclockwise?

Concretely, if for some digits A,B,C,D,E one had the identities A_PLUS_BC=DEF and ED=CB_PLUS_AF, where the latter can be formed by writing the former around a circle, cutting in a different place, and reading in the other direction, would this be a valid solution ? Or is the only legal way to write the identity A_PLUS_BC=DEF to actually write "A_PLUS_BC=DEF=" around the circle (with an extra equal sign) and both expressions must be formed by cutting the circle at an "=" sign ?

You can't break the expression wherever you want. If you write down your expressions many times in a row (or read in a circle an infinite number of times), then you should get the right equality. In the example , you can write 68=45_PLUS_23=68=45_PLUS_23=68= etc.
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 12:14 AM (#31481 - in reply to #31478) (#31481) Top


Moscow Puzzle Cup 2016 Author

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auroux - 2023-04-17 8:59 PM

After more thinking, I assume the correct interpretation is that we can break the circle anywhere we want (not necessarily at an = sign, and not necessarily in the same place in both directions), and that the example I gave would be a valid solution. Otherwise, it would have been easier to state the problem as producing an equality which is valid when read forwards and backwards (no need to use a circle).

The circle is used in the construction of letter palindromes, which are read an infinite number of times clockwise and counterclockwise, but sometimes giving different phrases. In Russia, such constructions are called cyclodromes.
auroux
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 12:21 AM (#31482 - in reply to #31480) (#31482) Top


Hex Slitherlink Author

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Riad Khanmagomedov - 2023-04-17 11:06 AMYou can't break the expression wherever you want. If you write down your expressions many times in a row (or read in a circle an infinite number of times), then you should get the right equality. In the example , you can write 68=45_PLUS_23=68=45_PLUS_23=68= etc.

Ok, thanks. But, uh, wait. Now I am concerned. Is there, then, a requirement to have at least two equal signs?
Otherwise, something like '98765*43210=' around the circle produces a valid equality when reading around the circle infinitely many times: 98765*43210=98765*43210=98765*43210=...
But this seems to violate the spirit of the puzzle, or at least there isn't much optimization left to do in this version.

And for completeness, can you clarify what exactly you expect in the answer key? The example given for the answer format only has one = sign given for each direction, even though there are two reading around the circle, so do we answer by giving what you get by cutting the circle open at an '=' sign and reading everything from just after that '=' sign to just before it, but not including the '=' sign along which we cut?

Sorry to be picky about details, but I think people spending time on this puzzle want to make sure that they are working on the correct version of it...


Thanks,Denis
prasanna16391
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 2:57 AM (#31483 - in reply to #31479) (#31483) Top


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jeff10 - 2023-04-17 9:26 PM

For the Bubbles Puzzle (Puzzle 2), do bubbles have to circle completely around an NxN (N=1,2,3) square of cells, or can a bubble of "size 3" only circle 3 of the leftmost cells while the center of the bubble is outside the grid?


The former.
prasanna16391
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 2:59 AM (#31484 - in reply to #31435) (#31484) Top


2021 World Sudoku+Puzzle Convention Organizer

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A new puzzle booklet has been uploaded to address some of the issues discussed in the previous page (puzzle 9 wording and puzzle 2 example's key)
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 11:26 AM (#31488 - in reply to #31482) (#31488) Top


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auroux - 2023-04-18 12:21 AM

Riad Khanmagomedov - 2023-04-17 11:06 AMYou can't break the expression wherever you want. If you write down your expressions many times in a row (or read in a circle an infinite number of times), then you should get the right equality. In the example , you can write 68=45_PLUS_23=68=45_PLUS_23=68= etc.

Ok, thanks. But, uh, wait. Now I am concerned. Is there, then, a requirement to have at least two equal signs?
Otherwise, something like '98765*43210=' around the circle produces a valid equality when reading around the circle infinitely many times: 98765*43210=98765*43210=98765*43210=...
But this seems to violate the spirit of the puzzle, or at least there isn't much optimization left to do in this version.

And for completeness, can you clarify what exactly you expect in the answer key? The example given for the answer format only has one = sign given for each direction, even though there are two reading around the circle, so do we answer by giving what you get by cutting the circle open at an '=' sign and reading everything from just after that '=' sign to just before it, but not including the '=' sign along which we cut?

Sorry to be picky about details, but I think people spending time on this puzzle want to make sure that they are working on the correct version of it...


Thanks,Denis

You must have 2, 3 or more equal signs. You can also get the equality 1 = 3-2 = 5-4 = with three equal signs and write it out endlessly in a circle. But at the same time, in the opposite direction, it must also be true.
auroux
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 11:40 AM (#31489 - in reply to #31435) (#31489) Top


Hex Slitherlink Author

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Ok thank you! Now it is clear.
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 16th to 23nd April 2023 @ 2023-04-18 2:31 PM (#31493 - in reply to #31489) (#31493) Top


Moscow Puzzle Cup 2016 Author

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auroux - 2023-04-18 11:40 AM

Ok thank you! Now it is clear.

It is allowed to use arithmetic signs on both sides of the equal sign.
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