Login Register WSPC 2017 • Schedule • Participation • Location • WSC • WPC • Contact •Search •Recent





TVC XI — 17th-19th March
   LMI Tests -> Annual Competitions57 posts • Page 1 of 3 • 1 2 3
anurag
Subject: Re: TVC XI — 17th-19th March @ 2012-03-14 7:46 PM (#6911 - in reply to #6885) (#6911) Top




Posts: 136
10020
Location: India
Meiosis: There is a possibility of single digit(even) clues breaking down to a single digit again(even or odd). Is that allowed? This will let two-digit clues breaking down to 2-digit clues again.the example does not show such behaviour.
yureklis
Subject: Re: TVC XI — 17th-19th March @ 2012-03-14 9:08 PM (#6912 - in reply to #6911) (#6912) Top


CTC & TVC Author & Organizer

Posts: 183
10020202020
Location: Turkey
anurag - 2012-03-14 7:46 PM

Meiosis: There is a possibility of single digit(even) clues breaking down to a single digit again(even or odd). Is that allowed? This will let two-digit clues breaking down to 2-digit clues again.the example does not show such behaviour.


As I understand correctly, you are asking this: If there is "2" in a cell, can it be only "1" after division, instead of "1-1"? The answer is no. Division here is not mathematical division, it is biological cell division, so something splits into two and both elements should be there.
prasanna16391
Subject: Re: TVC XI — 17th-19th March @ 2012-03-14 9:45 PM (#6913 - in reply to #6912) (#6913) Top


2021 World Sudoku+Puzzle Convention Organizer

Posts: 1788
100050010010020202020
Location: India
yureklis - 2012-03-14 9:08 PM

As I understand correctly, you are asking this: If there is "2" in a cell, can it be only "1" after division, instead of "1-1"? The answer is no. Division here is not mathematical division, it is biological cell division, so something splits into two and both elements should be there.


Now I'm well and truly confused .
If a "2" splits into "1-1", shouldn't a "1" split into "0.5-0.5" i.e. "0-5-0-5"? According to the way "1" is divided only into "0-5", "2" should be divided only into "1" I suppose.
anurag
Subject: Re: TVC XI — 17th-19th March @ 2012-03-14 11:11 PM (#6914 - in reply to #6912) (#6914) Top




Posts: 136
10020
Location: India
alright, thats clear now.However,the practice puzzle i made follows my earlier understanding of splitting an even number into a single half.An even digit splitting into 2 parts might feel something like math tapa with the + operator.
looks like Tapa is slowly transforming into applied tapa.Reproduction,cell division. Physics is next i think(i have one variation on that theme).

Edited by anurag 2012-03-14 11:14 PM
MellowMelon
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 12:08 AM (#6915 - in reply to #6914) (#6915) Top


Fillomino-Fillia 2 Author

100
Location: United States
I'm sorry, I'm still not clear on Meiosis Tapa. As I understand things now,
-- a 1 can either be used as a 1 or substituted for 0 5 (aka just 5)
-- a 2 can either be used as a 2 or substituted for 1 1
-- a 3 can either be used as a 3 or substituted for 1 5
-- a 4 can either be used as a 4 or substituted for 2 2
etc.
Is this correct? Also, can a clue divide twice? (4 becoming 2 1 1 for example)

Also, for Balance Tapa, for a puzzle of the size in the IB, is it only saying that the total number of black squares in columns 1,2,3 is the same as the total number of black squares in columns 5,6,7?

Edited by MellowMelon 2012-03-15 12:09 AM
Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 12:22 AM (#6916 - in reply to #6910) (#6916) Top




Posts: 315
100100100
Location: The Netherlands
yureklis - 2012-03-14 5:30 PM

Para - 2012-03-13 12:18 PM
Irregular Tapa:

1) The rules don't match the puzzle. It says that each shape is counted as one cell, except around the 3 clue are only 2 seperate shapess coloured. There are 3 cells coloured as one shape is 2 cells. So either the rules are incorrect or the example. The example currently doesn't match the way the variant appeared in the TVC before.


When I first replied to this problem, I couldn't remember why I made the puzzle that way, so I said there was a problem. But when I attempted for a fix I remembered that: I made the puzzle that way because large cells counting as one cell could be confusing for neighbouring boxes' types. So I counted them as multiple cells. But we accidentally used the actual puzzle's instruction. So this puzzle type is not Irregular, maybe it can be Ir-irregular, thus making it a regular Tapa with different cells.


But I just finished the Combined Tapa that way........

I figured it would just work the same for any edge clue. Although I didn't have any clues bordering the irregular tapa part.

I'll wait with the meiosis when it's completely confirmed.

Edited by Para 2012-03-15 12:28 AM
suboree
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 12:42 AM (#6917 - in reply to #6913) (#6917) Top




Posts: 9

Location: Turkey
prasanna16391 - 2012-03-14 9:45 PM

yureklis - 2012-03-14 9:08 PM

As I understand correctly, you are asking this: If there is "2" in a cell, can it be only "1" after division, instead of "1-1"? The answer is no. Division here is not mathematical division, it is biological cell division, so something splits into two and both elements should be there.


Now I'm well and truly confused .
If a "2" splits into "1-1", shouldn't a "1" split into "0.5-0.5" i.e. "0-5-0-5"? According to the way "1" is divided only into "0-5", "2" should be divided only into "1" I suppose.


Dear puzzlers, Gulce speaking. Serkan is so busy nowadays and I was the one to write the comment of Serkan above, didn't notice I was logged in with his account :) There is indeed a confusion with the rules, we have to set a constraint. Current example allows 2 becoming 1. Now I talked to him, he'll fix the rules when he gets back home. Sorry for causing trouble


Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 12:55 AM (#6918 - in reply to #6885) (#6918) Top




Posts: 315
100100100
Location: The Netherlands
I've posted the first 3 practise puzzles. Tomorrow the next 3 or 4 will be posted. The last few will come out on friday.

http://puzzleparasite.blogspot.com/2012/03/tvc-xi-practise-part-1.h...
Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 1:09 AM (#6919 - in reply to #6917) (#6919) Top




Posts: 315
100100100
Location: The Netherlands
There is indeed a confusion with the rules, we have to set a constraint. Current example allows 2 becoming 1. Now I talked to him, he'll fix the rules when he gets back home. Sorry for causing trouble


No worry. No real hurry for it. As long as it gets resolved.

Edited by Para 2012-03-15 2:25 AM
Yokipi
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 4:36 AM (#6922 - in reply to #6885) (#6922) Top




Posts: 5

Location: United States
Is relative order preserved in the Visionary Tapa clues? e.g. Is a 1234 different from a 1324?
yureklis
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 5:18 AM (#6923 - in reply to #6922) (#6923) Top


CTC & TVC Author & Organizer

Posts: 183
10020202020
Location: Turkey
Yokipi - 2012-03-15 4:36 AM

Is relative order preserved in the Visionary Tapa clues? e.g. Is a 1234 different from a 1324?


Order of the digits is not important, 1234 and 1324 are the same.
yureklis
Subject: RE: TVC XI — 17th-19th March @ 2012-03-15 5:20 AM (#6924 - in reply to #6885) (#6924) Top


CTC & TVC Author & Organizer

Posts: 183
10020202020
Location: Turkey
Corrections on the instructions are stated below. Meiosis Tapa will have a new example puzzle, edited version of the IB will be posted soon.

1. Combined Tapa:
Digital Tapa: Any digit has the possibility of being zero.
Ir-irregular Tapa: Each irregular shape counts as many cells as the unit squares it contains.

10. Meiosis Tapa:
Some of the given clue digits may be divided in half. This may happen in two different ways: Digit splits into two and creates two identical digits; or digit is only divided by two and results in a single number. Multi-digit clue cells may have divided and undivided digits together. If a digit divides in half and results in a decimal, each digit in the result counts as a new Tapa clue (e.g. if the original clue is 3, it becomes 1-5 after the division). Resulting digit of a division cannot be divided again.
Para
Subject: RE: TVC XI — 17th-19th March @ 2012-03-15 5:40 AM (#6925 - in reply to #6924) (#6925) Top




Posts: 315
100100100
Location: The Netherlands
yureklis - 2012-03-15 5:20 AM

10. Meiosis Tapa:
Some of the given clue digits may be divided in half. This may happen in two different ways: Digit splits into two and creates two identical digits; or digit is only divided by two and results in a single number. Multi-digit clue cells may have divided and undivided digits together. If a digit divides in half and results in a decimal, each digit in the result counts as a new Tapa clue (e.g. if the original clue is 3, it becomes 1-5 after the division). Resulting digit of a division cannot be divided again.


So if I get it right a 22 clue can be a either of the following:
22 (no division)
21 (one divided by two)
211 (one divided in two)
11 (two divided by two)
111 (one divided by two, one divided in two)
1111 (two divided in two)

Administrator
Subject: RE: TVC XI — 17th-19th March @ 2012-03-15 5:56 AM (#6926 - in reply to #6924) (#6926) Top


2000100050020
Location: India
yureklis - 2012-03-15 5:20 AM
Corrections on the instructions are stated below. Meiosis Tapa will have a new example puzzle, edited version of the IB will be posted soon.
Edited version of the IB is uploaded.
yureklis
Subject: RE: TVC XI — 17th-19th March @ 2012-03-15 6:34 AM (#6927 - in reply to #6925) (#6927) Top


CTC & TVC Author & Organizer

Posts: 183
10020202020
Location: Turkey
Para - 2012-03-15 5:40 AM

So if I get it right a 22 clue can be a either of the following:
22 (no division)
21 (one divided by two)
211 (one divided in two)
11 (two divided by two)
111 (one divided by two, one divided in two)
1111 (two divided in two)



Yes, all cases are possible.
anurag
Subject: RE: TVC XI — 17th-19th March @ 2012-03-15 11:51 AM (#6928 - in reply to #6924) (#6928) Top




Posts: 136
10020
Location: India
Sorry,this is a bit ridiculous,in my opinion.Having so many possibilities for a clue may only increase confusion.Its hard to figure out possibilities from the large mappings during the test.I believe it should be as simple as possible.
Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-15 11:54 PM (#6929 - in reply to #6885) (#6929) Top




Posts: 315
100100100
Location: The Netherlands
Maybe there should be a small clarification to the ir-iregular Tapa rules. Currently it reads that each shape counts as as many cells it contains. But that's not exactly correct as it could be interpretted that a 3 cell area which touch the Tapa clue with 1 cell is counted as 3 cells, even though it's only meant to be counted as 1 cell.
It's supposed to mean each cell in a shape counts towards a tapa clue if it's touching the clue.


On a side note. Can anyone explain how to approach the Full Tapa example? I don't see a way to get started.
Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-16 12:13 AM (#6931 - in reply to #6885) (#6931) Top




Posts: 315
100100100
Location: The Netherlands
Second set of practise puzzles have now been posted. Hope they help.

http://puzzleparasite.blogspot.com/2012/03/tvc-xi-practise-part-2.h...
Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-16 11:09 AM (#6933 - in reply to #6885) (#6933) Top




Posts: 315
100100100
Location: The Netherlands
How exactly does the answer key work for Fractional cells? If you look at row 4 or row 7 for example,it can get a bit confusing.


For row 7 is it
1,2,4 (count all squares that are touching as 1)
1,2,3 (the bottom of the fractional cell only)
1,2,1,1 (the top of the fractional cells only)
1,2,2.75 (all cells touching, but fractional cells counted as fractions like in the clues)

For row 4 it's even so that the fractioned cell has two seperate pathways running off the same cell.

Deb edited to add the solution image.

Edited by Para 2012-03-16 12:13 PM
anurag
Subject: Re: TVC XI — 17th-19th March @ 2012-03-16 5:47 PM (#6934 - in reply to #6929) (#6934) Top




Posts: 136
10020
Location: India
If R6C6 is used by a vertical word,it can be One ,zero,two,six or four.One,two,six fail as it leaves a white space of 2 cells in the top-right corner.Four or zero leave R6C3-4 white,so they fail too.that leaves r6C6 with a horizontal word,which is atleast 4 long to satisfy the black block in the last row.A 4-letter word would leave a V-shaped 5 which leaves a white space in R5 that cant be filled.So only three can use the 6th row.This completes 6 and the entire right half.R1C6 must be black.Done!

Edited by anurag 2012-03-16 5:52 PM
anurag
Subject: Re: TVC XI — 17th-19th March @ 2012-03-16 5:50 PM (#6935 - in reply to #6929) (#6935) Top




Posts: 136
10020
Location: India
Correct, the rules are badly written
Administrator
Subject: Re: TVC XI — 17th-19th March @ 2012-03-16 10:38 PM (#6941 - in reply to #6885) (#6941) Top


2000100050020
Location: India
PuzzlePointsGroup
1. Combined Tapa154Puzzles 1-3
2a. Mad Max Tapa13Puzzles 1-3
2b. Mad Max Tapa136Puzzles 1-3
3. Fractional Tapa55Puzzles 1-3
4. Dissected Tapa63Puzzles 4-7
5. Visionary Tapa138Puzzles 4-7
6. Full Tapa146Puzzles 4-7
7. Modern Tapa43Puzzles 4-7
8. Power of Tapa192Puzzles 8-10
9. Tapa Balance47Puzzles 8-10
10. Meiosis Tapa64Puzzles 8-10

Announcements

Password protected pdf is uploaded. It has 10 pages (including a cover page)
Time bonus will be computed after you click "Claim Bonus"
Penalty will be given irrespective of correctness of submission



Contest Length : 75 minutes
Total Points : 1051
Bonus : 10 points per minute saved
Grace Period : 5 minutes
Penalty : 8 points per minute used (Computed upto seconds)


Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-16 11:54 PM (#6942 - in reply to #6885) (#6942) Top




Posts: 315
100100100
Location: The Netherlands
Last set of practise puzzles are posted. I hope they have been helpful.

http://puzzleparasite.blogspot.com/2012/03/tvc-xi-practise-part-3.h...
Para
Subject: Re: TVC XI — 17th-19th March @ 2012-03-17 6:35 AM (#6943 - in reply to #6933) (#6943) Top




Posts: 315
100100100
Location: The Netherlands
Para - 2012-03-16 11:09 AM

How exactly does the answer key work for Fractional cells? If you look at row 4 or row 7 for example,it can get a bit confusing.


For row 7 is it
1,2,4 (count all squares that are touching as 1)
1,2,3 (the bottom of the fractional cell only)
1,2,1,1 (the top of the fractional cells only)
1,2,2.75 (all cells touching, but fractional cells counted as fractions like in the clues)

For row 4 it's even so that the fractioned cell has two seperate pathways running off the same cell.

Deb edited to add the solution image.


Can this question be answered, please? It seems kinda important for the test to know how the answer key works for this particular type. If it's irrelevant because no fractional cells will be in the answer rows and columns that would also help to know.

Edited by Para 2012-03-17 6:37 AM
MellowMelon
Subject: Re: TVC XI — 17th-19th March @ 2012-03-17 7:34 AM (#6944 - in reply to #6943) (#6944) Top


Fillomino-Fillia 2 Author

100
Location: United States
Para: The test's puzzle did not mark rows or columns with a divided cell, so it's fine. (edit: ok'd to say this by Deb in an email)

Thanks for the great test. As my post in this topic suggested and as my comment on motris's blog made more explicit, I was really worried about the set of variations here, but the test turned out to be the load of fun a TVC usually is. Happy with how I did, but taking it so early means it's a long wait to see how I compare with others...

Edited by MellowMelon 2012-03-17 7:52 AM
57 posts • Page 1 of 3 • 1 2 3
Jump to forum :
Search this forum
Printer friendly version