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Riad Khanmagomedov's April Contest — 4th - 12th April 2014
   LMI Tests -> Annual Competitions98 posts • Page 3 of 4 • 1 2 3 4
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-08 10:19 PM (#14880 - in reply to #14877) (#14880) Top


2000100050020
Location: India
swaroop2011 - 2014-04-08 9:36 PM

just a query
for answer key of Trid and sudoku on cube we have to enter 9,9,9,9.. or 99999 without commas ?
Both formats are accepted (in this contest and in all other contests at LMI)
Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-08 11:22 PM (#14881 - in reply to #14642) (#14881) Top




Posts: 67
202020
Location: France
Small question about Battleships: When you say "Maximum length of horizontal / vertical line segments", do you mean "CONSECUTIVE horizontal / vertical line segments"? Otherwise, in the example, the top right corner '2' is actually 2 1/2 long.
spelvin
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-09 1:29 AM (#14882 - in reply to #14843) (#14882) Top




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Location: United States
Riad Khanmagomedov - 2014-04-07 9:30 AM

Grizix - 2014-04-07 7:12 PM

Hi

In the My Line quadrant, does a segment of turn could leave the quadrant ? For example, can the 2 on the last row have a segment of his turn crossing the quadrant border ?
Does crossing the border cuts the length of a segment ? For example, with the 1 near the median horizontal border, could it cross this border and still count as one segment ? (as there is only one segment IN the quadrant)

Nice puzzles anyway !

Yes, a segment of turns can leave the quadrant. In the example I specifically gave one such angle (in cell with "?").


Similar question for Battleships With Line: can a row or column have a longer segment which is partially outside the quadrant, if the portion within the quadrant is below the given maximal length?
swaroop2011
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-09 3:52 AM (#14884 - in reply to #14881) (#14884) Top



PR 2020 (Shading and Loops) Author

Posts: 668
500100202020
Location: India
Small question about Battleships: When you say "Maximum length of horizontal / vertical line segments", do you mean "CONSECUTIVE horizontal / vertical line segments"? Otherwise, in the example, the top right corner '2' is actually 2 1/2 long.


yes you can say it is consecutive segments



Edited by swaroop2011 2014-04-09 3:54 AM
kiwijam
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-09 3:54 AM (#14885 - in reply to #14879) (#14885) Top




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devarajand - 2014-04-09 5:18 AM
In Trid can the numbers be repeated in the diagonals. That is the bold diagonals of rectangle/sides of triangles.


There are 6 small Trid puzzles, each has bold borders that are 7 circles long.
Numbers can NOT be repeated along those 7-circle borders, or any other diagonal within the same small triangle.
(it's the same idea as the Sudoku On Cube puzzle, there are 6 little puzzles with individual solutions, but they have identical digits along their common borders)
Riad Khanmagomedov
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-09 12:48 PM (#14886 - in reply to #14882) (#14886) Top


Moscow Puzzle Cup 2016 Author

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spelvin - 2014-04-09 1:29 AM

Riad Khanmagomedov - 2014-04-07 9:30 AM

Grizix - 2014-04-07 7:12 PM

Hi

In the My Line quadrant, does a segment of turn could leave the quadrant ? For example, can the 2 on the last row have a segment of his turn crossing the quadrant border ?
Does crossing the border cuts the length of a segment ? For example, with the 1 near the median horizontal border, could it cross this border and still count as one segment ? (as there is only one segment IN the quadrant)

Nice puzzles anyway !

Yes, a segment of turns can leave the quadrant. In the example I specifically gave one such angle (in cell with "?").


Similar question for Battleships With Line: can a row or column have a longer segment which is partially outside the quadrant, if the portion within the quadrant is below the given maximal length?

No, cannot.
Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-09 10:26 PM (#14889 - in reply to #14884) (#14889) Top




Posts: 67
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Location: France
OK, thanks. Since the beginning, I had misinterpreted the statement of 'Battleship with Line'. When I finally properly translated, it became (almost) easy ...
Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-09 10:33 PM (#14890 - in reply to #14642) (#14890) Top




Posts: 67
202020
Location: France
Hi. Another question: For optimization problems, I guess you can without penalty propose a first solution, then return it to improve, right?
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-09 10:45 PM (#14891 - in reply to #14890) (#14891) Top


2000100050020
Location: India
Puzlifouk - 2014-04-09 10:33 PM

Hi. Another question: For optimization problems, I guess you can without penalty propose a first solution, then return it to improve, right?

Yes. There is no penalty.
Your final submission for each puzzle will be considered for scoring.
sduran
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-10 1:02 AM (#14892 - in reply to #14642) (#14892) Top




Posts: 7

Location: Turkey
according to diayajilin rules;

1-digit in a cell shows total number of black cells on its both diagonals
2-or shows total number of black cells on its any diagonals

for example;

digit 2 in a cell and there is 2 black cells on any of its diagonal and there is one black cell on its other diagonal. that is satisfied the rule?


kiwijam
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-10 2:49 AM (#14893 - in reply to #14892) (#14893) Top




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sduran - 2014-04-10 8:02 AM

according to diayajilin rules;

1-digit in a cell shows total number of black cells on its both diagonals
2-or shows total number of black cells on its any diagonals

for example;

digit 2 in a cell and there is 2 black cells on any of its diagonal and there is one black cell on its other diagonal. that is satisfied the rule?


In Diayajilin, if there is a digit "2" in a cell then this is the total of all black cells in both diagonals, added together.

i.e.
there is 1 black in NW-SE diagonal and 1 black in NE-SW diagonal
OR
there is 2 blacks in NW-SE diagonal and 0 blacks in NE-SW diagonal
OR
there is 0 blacks in NW-SE diagonal and 2 blacks in NE-SW diagonal

(but you can NOT have 2 blacks in NW-SE diagonal and 1 black in NE-SW diagonal)
devarajand
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-10 6:21 AM (#14894 - in reply to #14642) (#14894) Top




Posts: 114
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Location: India
In my line if there is a no 2 is it necessary to have the length of lines equal to 2 on both sides or on side is enough.
swaroop2011
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-10 7:24 AM (#14896 - in reply to #14894) (#14896) Top



PR 2020 (Shading and Loops) Author

Posts: 668
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both sides its necessary

devarajand - 2014-04-10 6:21 AM

In my line if there is a no 2 is it necessary to have the length of lines equal to 2 on both sides or on side is enough.

Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-10 10:24 AM (#14897 - in reply to #14642) (#14897) Top




Posts: 67
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Location: France
Hi.
For 'Roman OX', I thought it was possible to use 'X' AND 'O' inside the grid, but the submission page specifies to use only 'X' and '-' ?
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-10 11:32 AM (#14898 - in reply to #14897) (#14898) Top


2000100050020
Location: India
Puzlifouk - 2014-04-10 10:24 AM

Hi.
For 'Roman OX', I thought it was possible to use 'X' AND 'O' inside the grid, but the submission page specifies to use only 'X' and '-' ?
Fixed. Your submission was already accepted nevertheless.
sduran
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-10 9:24 PM (#14900 - in reply to #14642) (#14900) Top




Posts: 7

Location: Turkey
For the puzzle 10;

I cannot figure out by equal dimension of figure and grid cells on the given example.
Could you explain pls.
kiwijam
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-11 2:44 AM (#14902 - in reply to #14900) (#14902) Top




Posts: 187
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Location: New Zealand
sduran - 2014-04-11 4:24 AM

For the puzzle 10;
I cannot figure out by equal dimension of figure and grid cells on the given example.
Could you explain pls.


It means that the shapes must cover grid cells exactly. e.g. You cannot place the 1x1 shape to cover half of one grid cell and half of another grid cell.
Grizix
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-11 4:27 AM (#14903 - in reply to #14642) (#14903) Top




Posts: 30
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Location: France
Another question, about Battleships with Line :
Does the maximum line length have to exist or is it just a maximum ?
In other words, for a row with a 2, do we need to have at least one line of length 2 or only 1 length lines is ok ?
greenhorn
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-11 4:42 AM (#14904 - in reply to #14903) (#14904) Top


2021 World Sudoku+Puzzle Convention Organizer

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Grizix - 2014-04-11 4:27 AM

Another question, about Battleships with Line :
Does the maximum line length have to exist or is it just a maximum ?
In other words, for a row with a 2, do we need to have at least one line of length 2 or only 1 length lines is ok ?


It is needed to have such a lenght.
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-11 7:41 PM (#14907 - in reply to #14642) (#14907) Top


2000100050020
Location: India

Please check your submissions carefully before the contest ends

Because there is no manual override in this contest.


Puzlifouk
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-13 3:05 PM (#14913 - in reply to #14642) (#14913) Top




Posts: 67
202020
Location: France
Hello,
I really enjoyed this contest, with dense and varied problems. As a beginner, I always lack of time to look for problems in the usual competitions. This time, I only missed a little time to improve my optimizations ...
By the way, when can we expect to have the final results?
debmohanty
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-13 3:38 PM (#14914 - in reply to #14913) (#14914) Top



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Location: India
Puzlifouk - 2014-04-13 3:05 PM

Hello,
I really enjoyed this contest, with dense and varied problems. As a beginner, I always lack of time to look for problems in the usual competitions. This time, I only missed a little time to improve my optimizations ...
By the way, when can we expect to have the final results?


We still are working on the optimizers (to check correctness of submission). Riad is going to solve all of them soon.
Administrator
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-13 3:43 PM (#14915 - in reply to #14907) (#14915) Top


2000100050020
Location: India

Optimizers Submissions

Like previous year, we have created a pdf with submissions to all optimizer puzzles.

Click here to download.

Please note that Riad has not checked the correctness of the submissions yet. (So you probably can help him if you point out any mistakes in the pdf )

chaotic_iak
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-13 4:15 PM (#14916 - in reply to #14642) (#14916) Top



Typed Logic Author

Posts: 241
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Location: Indonesia
I like how there are essentially only six distinct submissions among those in Roman OX with score less than 200.

The 26x13 was amazing. I tried something similar but couldn't get 6 strands to run zigzagging like that because I ran out of minoes. But I tried it on 26x12; I should have tried 26x13 indeed. My first submission was a 26x8 with a T-tetromino at D1-E1-F1-E2, a monomino at A26, and a L-trimino at G26-H25-H26; something like the 26x8 on the booklet but with less minoes used. And obviously it can be extended at will, so a good thing there's that 26x26 limitation, too. (My submission is different, improved from the above.)

Meanwhile, time to guess the author!
Semax
Subject: Re: Riad Khanmagomedov's April Contest — 4th - 12th April 2014 @ 2014-04-13 6:28 PM (#14917 - in reply to #14642) (#14917) Top




Posts: 10

Location: Germany
Mine is the second one, 13x23. I could not place the last piece to make the rectangle longer, but even if I could have, the 13x26 would still be so much better. I just didn't think of putting the pieces directly at the left border...
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