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Posts: 102
Location: United States | A few starting thoughts (though no major break-ins):
1) You can eliminate some spaces (the red slashes) because of the existing directions in regions (e.g. R1C6 is north of the N in the region).
2) You can eliminate some spaces (the green slashes) because the only possible entry is already in that row/column (e.g. R1C3 is northwest of the S, but the column already has an N and a W).
3) There are 22 regions (so 44 letters) and 12 rows/columns. Each type of letter can only go in 11 different rows/columns (e.g. there can't be an S in the top column), so every letter must be in 11 of 12 rows/columns.
4) This isn't included in the picture, but the region containing R5C7 can't have an N or S in it, so there must be a W in R5C7 (I'm sure this can be used elsewhere too).
Edited by ghirsch 2015-08-20 11:31 PM
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SM 2020 (Math) Author
Posts: 419
Location: India | Hi ghirsch. Thanks a lot for the starters.However,I am still not clear.How did you shade R2C5/C6/C7 and lots of other squares too.For instance ,why can't be a E present in R2C5 (East of South) and a W present in R1C6 and R2C6/7 (West of North)
The region containing W(R9C3) has E in R12C5 as per solution.How is it even possible?? E has to be right opposite W right?I mean in line with W.How's it located to the lower right of it or in words South East of it? |
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PR 2020 (Shading and Loops) Author
Posts: 668
 
Location: India | kishy72 - 2015-08-21 12:17 AM
Hi ghirsch. Thanks a lot for the starters.However,I am still not clear.How did you shade R2C5/C6/C7 and lots of other squares too.For instance ,why can't be a E present in R2C5 (East of South) and a W present in R1C6 and R2C6/7 (West of North)
The region containing W(R9C3) has E in R12C5 as per solution.How is it even possible?? E has to be right opposite W right?I mean in line with W.How's it located to the lower right of it or in words South East of it?
Hi Kishy & ghirsch,
I believe you have not interpreted rules correctly.
The alphabets has to just follow the sense of direction.
What I meant by this is, E just has to be on right hand side of W, it doesn't need to be in line with W. it can be up or down but right side.
E.g. Consider the region R8C5 "W" clue region. E can be in R8C6, R7C6 or R9C6 but it cannot be at R12C5.
Similarly for N, W , S as well.
Another example S has to be on right side and at same time downside of W.
Check this given example for clarity:
http://logicmastersindia.com/lmitests/dl.asp?attachmentid=147&view=... |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1811
Location: India | kishy72 - 2015-08-21 12:17 AM
Hi ghirsch. Thanks a lot for the starters.However,I am still not clear.How did you shade R2C5/C6/C7 and lots of other squares too.For instance ,why can't be a E present in R2C5 (East of South)
Because then S won't be South of E. Look at it both ways, simply. |
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SM 2020 (Math) Author
Posts: 419
Location: India | Thanks Swaroop and Prasanna ! I could proceed till here after which it's too difficult .Where am I missing the trick?
Edited by kishy72 2015-08-22 12:11 AM
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Classics & Regions (PR 2016/17) Author
Posts: 170
Location: Germany | The upside down L tetromino must have an N in the top row. Then you get an NW-pair in row 3. |
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SM 2020 (Math) Author
Posts: 419
Location: India | rob - 2015-08-22 2:06 AM
The upside down L tetromino must have an N in the top row. Then you get an NW-pair in row 3.
I don't see how the former leads to the latter?! Where is the NW pair that you refer in row 3?How did you deduce that? |
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PR 2020 (Shading and Loops) Author
Posts: 668
Location: India | Hi kishy,
I haven't solved completely but looking at your image, I can tell you next few steps immediately:
1) R5C9 and R5C10 --> N will come in that region no matter what and in one of these places. (you can see what happens if N will not come)
2) Because of this R5C12 will be cross.
3) Now this gives N-W pair in Row 3, N or W at R3 -C5C6 AND N OR W at R3 C11-12.
4) So this eliminates N at R3 C1C2.
5) So this gives "S" at R5C1 and "E" at R3C2. So that will give "S" at r8c3.
I believe it should go easy after this.
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SM 2020 (Math) Author
Posts: 419
Location: India | I can't thank you enough Swaroop.I have done and dusted the puzzle finally and that's a tremendous relief after breaking my head for close to 2 days.The way you explained about that NW Pair in point 3 made me see clearly what I failed to observe.... |
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SM 2020 (Math) Author
Posts: 419
Location: India | A Numberlink puzzle.I realized that this puzzle has many ways of completing itself.Where am I going wrong?
Edited by kishy72 2015-08-30 2:50 PM
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SM 2020 (Math) Author
Posts: 419
Location: India | In addition,in the above puzzle,I had to use the constraint that all cells need to be visited by paths without which I found 'n' number of ways of completing this puzzle.Is there something critical that I am missing here? |
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Location: India | kishy72 - 2015-08-30 2:49 PM
A Numberlink puzzle.I realized that this puzzle has many ways of completing itself.Where am I going wrong?
This was a broken puzzle (I suppose you have taken this from one old LMI test)
Talking about Numberlink in general, this write up (Numberlink Primer) by Palmer will be an eye-opener for most. |
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SM 2020 (Math) Author
Posts: 419
Location: India |
This was a broken puzzle (I suppose you have taken this from one old LMI test)
Ah! I see.....It was taken from Nikoli Selection 2010 LMI monthly test.
Talking about Numberlink in general, this write up ( Numberlink Primer) by Palmer will be an eye-opener for most.
Thanks a lot Deb!I will look through this primer. |
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SM 2020 (Math) Author
Posts: 419
Location: India | I ran into some problems in the following Hitori puzzle with just a few steps away from completion.Despite being so close,I fail to see a logical continuation here. Can someone post the solution ?
Edited by kishy72 2015-08-31 7:10 PM
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PR 2020 (Shading and Loops) Author
Posts: 668
Location: India | kishy72 - 2015-08-31 6:45 PM
I ran into some problems in the following Hitori puzzle with just a few steps away from completion.Despite being so close,I fail to see a logical continuation here. Can someone post the solution ?
one quick next step: R1C2 will be shaded.
Reason: Either of R8C1 or R8C2 will be shaded so that means R7C2 is unshaded in any case. Hence above step. |
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SM 2020 (Math) Author
Posts: 419
Location: India | swaroop2011 - 2015-08-31 8:07 PM
kishy72 - 2015-08-31 6:45 PM
I ran into some problems in the following Hitori puzzle with just a few steps away from completion.Despite being so close,I fail to see a logical continuation here. Can someone post the solution ?
one quick next step: R1C2 will be shaded.
Reason: Either of R8C1 or R8C2 will be shaded so that means R7C2 is unshaded in any case. Hence above step.
Thank you ! I failed to see the 7 getting trapped.Done with the puzzle. |
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SM 2020 (Math) Author
Posts: 419
Location: India | A very difficult Hitori Puzzle ! Can someone please post the continuation here where I am stuck?
Edited by kishy72 2015-09-02 1:43 AM
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PR 2020 (Shading and Loops) Author
Posts: 668
Location: India | hi,
can you share the original puzzle link ?
I am confused whether what you have circled or not.
E.g. Is R6C5 "4" clue circled or not ? |
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SM 2020 (Math) Author
Posts: 419
Location: India | swaroop2011 - 2015-09-02 2:18 AM
hi,
can you share the original puzzle link ?
I am confused whether what you have circled or not.
E.g. Is R6C5 "4" clue circled or not ?
Sorry.You are right.It's not something which I deduced logically.I forgot to erase it. |
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PR 2020 (MII and Regions) Author
Posts: 55
Location: India | R6c5 "4:" clue should be unshaded only. |
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PR 2020 (MII and Regions) Author
Posts: 55
Location: India | If u see all the digits above and below the numbers at R7C5/7/9/11. for each number the digits above and below is same.. so if R6C5 is shaded then for the other numbers if any of the above or
below clue is shaded the white cells get closed at top |
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SM 2020 (Math) Author
Posts: 419
Location: India | ashaash11ash - 2015-09-02 9:18 AM
If u see all the digits above and below the numbers at R7C5/7/9/11. for each number the digits above and below is same.. so if R6C5 is shaded then for the other numbers if any of the above or
below clue is shaded the white cells get closed at top
Indeed.I missed this totally.The puzzle is still very sticky even after this deduction.But it helped a lot and I completed it .Thanks. |
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Posts: 56
Location: India | Just gone through the puzzle solving techniques. It's just amazing and very knowledgeable. I have learned a lot from it. |
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SM 2020 (Math) Author
Posts: 419
Location: India | The incorrectly done Mochikoro puzzle where all islands are not connected solved in the last few mins of the test .Apparently,there are ways one can gain points by solving incorrectly too !
Edited by kishy72 2015-12-22 6:59 PM
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1811
Location: India | I too gained points by solving incorrectly, in a more indirect way. I solved the Japanese Sums 25 pointer incorrectly by placing a digit by mistake where it shouldn't be, which enabled me to reach an incorrect solution and move to the 105 pointer much faster than I would have if I had solved correctly. Considering I solved the 105 pointer with 1 minute to spare, I'd say the mistake gained me 80 points  |
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