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Fugitive Warrant — November Sudoku Test - 3rd-5th November
   LMI Tests -> Monthly Sudoku and Puzzle Tests42 posts • Page 2 of 2 • 1 2
Spica
Subject: Re: Fugitive Warrant — November Sudoku Test - 3rd-5th November @ 2012-11-06 9:02 PM (#8930 - in reply to #8928) (#8930) Top


Fugitive Warrant Author

Posts: 3

Location: South Korea		joshuazucker// Thanks for enjoy our Sudokus.
Weighted Killer(Spoiler!!) : See http://home.postech.ac.kr/~meso/sudoku/weighted_killer.html
When I made this problem, Kwaka found that solution route very quickly. That's why we give (relatively) low points on this hard problem. Sorry for that

Spoiler: show
Once you add the cages at two bottom rows(with additional cell R7C8), then you can get the clue. Since R8C5 and R8C6 can not be both 1 at the same time, the sum 96 is the minimum possible value. Hence R9C1 = R7C8 = 1 and we have a multiple set {R8C5, R8C6} = {1,2}. That is the starting point I intended. If it is not enough, the sum of first row also gives you many informations.
joshuazucker
Subject: Re: Fugitive Warrant — November Sudoku Test - 3rd-5th November @ 2012-11-07 1:56 AM (#8931 - in reply to #8930) (#8931) Top




Posts: 31
20
Location: United States		Yeah, I got stuck after finding the 389 in the middle of the top and finding the shaded 1s and 2s in the bottom rows ... what next?
Spica
Subject: Re: Fugitive Warrant — November Sudoku Test - 3rd-5th November @ 2012-11-07 6:48 AM (#8935 - in reply to #8931) (#8935) Top


Fugitive Warrant Author

Posts: 3

Location: South Korea		joshuazucker// See also http://home.postech.ac.kr/~meso/sudoku/weighted_killer.jpg

Spoiler: show
joshuazucker
Subject: Re: Fugitive Warrant — November Sudoku Test - 3rd-5th November @ 2012-11-07 9:02 AM (#8936 - in reply to #8828) (#8936) Top




Posts: 31
20
Location: United States		Thanks for all the help! You're still earlier in the solve than the spot where it got hard for me.
42 posts • Page 2 of 2 • 1 2
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