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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1801
  
Location: India | deu - 2017-10-09 9:53 AM
13,14. Rectangular Numbers
Is it necessary to use each number (1,2,3 and 4) at least once?
No, not necessary. |
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Sudoku Day Author
Posts: 103
Location: Serbia | About duration of this round, it stands 10:10-11.50 and 80 minutes. Which one is correct? |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1801
Location: India | Nikola - 2017-10-10 12:27 PM
About duration of this round, it stands 10:10-11.50 and 80 minutes. Which one is correct?
80 minutes is correct. Will need to get the schedules fixed. This will be done. For now you may refer here for the reflection of the changes roughly (some spacing considerations are included so it isn't just moving 20 minutes backward everywhere) - http://wspc2017.logicmastersindia.com/?g=Schedule2017 |
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Classics & Regions (PR 2016/17) Author
Posts: 170
Location: Germany | Re Candy Crush, I read the rules to say that the solution can't contain three or more equal letters in a straight line, horizontal or vertical. On the other hand, elimination happens for any group of edge-connected equal letters of size at least three, e.g., for an L-trimino. Is that correct?
Second, why can't the top two rows of the example solution be ADBDBB,AADXDC? Is it because swapping e.g. R1C1 and R1C2 doesn't for a "new" group? |
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Posts: 225
Location: Thailand | (3,4) Shards: Can some of the fragments that make up each shard be connected by a point? (Ie. could there be a shard where, say, three fragments are connected by edges and one "hanging"
off a vertex?)
(21,22) Grapevine: Can the branch enter/leave a grape from a triangular cell? |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1801
Location: India | rob - 2017-10-11 11:56 PM
Re Candy Crush, I read the rules to say that the solution can't contain three or more equal letters in a straight line, horizontal or vertical. On the other hand, elimination happens for any group of edge-connected equal letters of size at least three, e.g., for an L-trimino. Is that correct?
Second, why can't the top two rows of the example solution be ADBDBB,AADXDC? Is it because swapping e.g. R1C1 and R1C2 doesn't for a "new" group?
Not an L- Trimino. The rule says "horizontally or vertically consecutive cells" which means three letters in a line along a row, or a column. This may answer the second part too? |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1801
Location: India | tamz29 - 2017-10-12 10:28 AM
(3,4) Shards: Can some of the fragments that make up each shard be connected by a point? (Ie. could there be a shard where, say, three fragments are connected by edges and one "hanging"
off a vertex?)
(21,22) Grapevine: Can the branch enter/leave a grape from a triangular cell?
3,4: No. For a shard all its fragments are edge-connected.
21,22: No. Vines travel via edges only. Its not explicitly mentioned though. We will make a note of this during Q&A. |
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SM 2020 (Math) Author
Posts: 419
Location: India | Puzzle 11,12 : Partiti
The rules state same digits cannot be placed in cells touching diagonally.Can same digits be placed in a single cell ? For instance, can the 2 sum be 1,1 if it doesn't violate the no touch rule with other cells?This case doesn't occur in the example . |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1801
Location: India | kishy72 - 2017-10-14 3:24 PM
Puzzle 11,12 : Partiti
The rules state same digits cannot be placed in cells touching diagonally.Can same digits be placed in a single cell ? For instance, can the 2 sum be 1,1 if it doesn't violate the no touch rule with other cells?This case doesn't occur in the example .
No. We will clarify this at Q&A too. |
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Posts: 9
Location: Finland | 15,16 Maximal Archipelago
Having R6C2 as sea and R7C1 + R7C3 as land and everything else as in example solution - would that be viable solution? If not, please explain why. |
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2021 World Sudoku+Puzzle Convention Organizer
Posts: 1801
Location: India | UllaE - 2017-10-14 6:46 PM
15,16 Maximal Archipelago
Having R6C2 as sea and R7C1 + R7C3 as land and everything else as in example solution - would that be viable solution? If not, please explain why.
It wouldn't because then there is no case within a and b where the given Sea cell in R4C4 has to be a Sea cell. |
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Posts: 9
Location: Finland | Thanks, didn't notice that :-) |
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