stuck in this sudoku | |
LMI Essentials -> Solving Techniques | 159 posts • Page 1 of 7 • 1 2 3 4 5 6 7 |
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | hi.i m posting this sudoku taken from fed sudoku.yours truthfully has reached till this point without any problem but was unable to proceed beyond this point even after trying miserably for 20 mins.So people who solve sudokus unbelievably fast and make others blink in amazement!help this poor fellow to see light in this sudoku. Edited by kishy72 2012-09-21 8:53 PM | ||
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Location: India | Hi Kishore, After uploading the image in http://tinypic.com you will get "HTML for Websites". Copy that and paste in your post. "HTML for Websites" will look like : <a href="http://tinypic.com?ref=1zn20so" target="_blank"><img src="http://i47.tinypic.com/1zn20so.png" border="0" alt="Image and video hosting by TinyPic"></a> You can also copy and paste "Direct Link for Layouts" which looks like : http://i47.tinypic.com/1zn20so.png | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | i am posting the link...thnks deb.i could not have posted this without your help. | ||
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Location: India | Focus on R7C2 and R9C2 and column 2. You should be able find the next steps. Spoiler: show Given that you have already marked R2C2 and R8C2 as 78, R7C2 and R9C2 have naked pair 36. So R5C3 is 6 and R5C2 is 9. Edited by debmohanty 2012-09-21 10:05 PM | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | Administrator - 2012-09-21 9:51 PM Focus on R7C2 and R9C2 and column 2. You should be able find the next steps. Spoiler: show Given that you have already marked R2C2 and R8C2 as 78, R7C2 and R9C2 have naked pair 36. So R5C3 is 6 and R5C2 is 9. hi i m not getting it.How did u lock (3/6)in (R7C2 /R9C2).(3 and 6) eliminated from R2C2,R3C2,R4C2-perfectly ok.But only 3 is getting eliminated from R5C2 .So 6 might be present in R5C2 right?!correct me if i am missing something. | ||
prasanna16391 |
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2021 World Sudoku+Puzzle Convention Organizer Posts: 1801 Location: India | kishy72 - 2012-09-22 11:44 AM Administrator - 2012-09-21 9:51 PM Focus on R7C2 and R9C2 and column 2. You should be able find the next steps. Spoiler: show Given that you have already marked R2C2 and R8C2 as 78, R7C2 and R9C2 have naked pair 36. So R5C3 is 6 and R5C2 is 9. hi i m not getting it.How did u lock (3/6)in (R7C2 /R9C2).(3 and 6) eliminated from R2C2,R3C2,R4C2-perfectly ok.But only 3 is getting eliminated from R5C2 .So 6 might be present in R5C2 right?!correct me if i am missing something. In the bottom left box, the only digits that can be there are 3,6,7,8 right? Now in C2, you already have a place in R2 for 7-8, and R8 for 7-8. So 7-8 can't be in any of the rest of the cells in C2. So, R7 and R9 of C2 cannot have 7-8, and the only remaining digits that are possible from the original 4 is 3 and 6. | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | So basically R9C3 contains either 7 or 8 and therefore......................clear now . will be posting many more stuck sudokus .Thanks guys! | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | second in the list of sudokus ....where i m unable to cross beyond this point ...fatigue sets in after a certain point...not able to lock any number after this .... | ||
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Location: India | Where do you put 2 in column 3? Spoiler: show Given that you have already marked triplets 2/3/4 in row 3 (C5,C8,C9), R3C3 can not be 2 It should solve pretty smoothly after that. | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | Administrator - 2012-09-23 8:28 PM Where do you put 2 in column 3? Spoiler: show Given that you have already marked triplets 2/3/4 in row 3 (C5,C8,C9), R3C3 can not be 2 It should solve pretty smoothly after that. Beautiful!i completed very fast after putting that number...great spotting!...hope i remember these small intricacies and implement them in future sudokus.thnk u ! | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | third in the series of stuck sudokus... how do i proceed from here fellas?! | ||
prasanna16391 |
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2021 World Sudoku+Puzzle Convention Organizer Posts: 1801 Location: India | R1C6 can only be 5-7 due to normal single eliminations of 3,6,2. Similarly, R1C5 can only be 2-5-7. As you have already marked R1C9 as 5-2, that makes a triplet meaning 7 can only be in R1C5/6. It can also only be in R5C5/6, as you have marked. So in C4, you get just one spot to place the 7. | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | prasanna16391 - 2012-09-25 4:59 PM R1C6 can only be 5-7 due to normal single eliminations of 3,6,2. Similarly, R1C5 can only be 2-5-7. As you have already marked R1C9 as 5-2, that makes a triplet meaning 7 can only be in R1C5/6. It can also only be in R5C5/6, as you have marked. So in C4, you get just one spot to place the 7. amazing ..and here was i under the false assumption all these years that all it takes to solve a sudoku is a set of simple rules and logic when the tricks to be learnt in the trade is endless....i know i certainly wouldn't have placed that 7 after making that deduction of locking it in R1C5/R1C6....i m learning new tricks in sudoku ....all the 3 sudokus i failed to solve has some triplets...!!!!!i feel i m improving gradually after joining LMI....thnks prasanna! Edited by kishy72 2012-09-25 7:50 PM | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | 4th in the series ..help me out on this one fellas....hope u guys are not too busy in prep for wc...i am sure i combed the entire sudoku for triplets and could not notice any Edited by kishy72 2012-09-27 11:05 PM | ||
prasanna16391 |
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2021 World Sudoku+Puzzle Convention Organizer Posts: 1801 Location: India | I remember how I solved this one(thats a rarity, I generally struggle to re-solve things). Anyway, see R2 and R8. whichever way you see it, R2/8C6 has to be 1/3. Should be simple to see, say 1 and 3 are in R2C4 and C5, then both have to be in R8C6, and vice versa. So R7C6 has to be 6. | ||
akash.doulani |
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SM 2020 (Math) Author Posts: 157 Location: India | there is a triplet of 458 in r1r3r5/c6. after that u get a 6 in r7c6. its plain solving after that | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | akash.doulani - 2012-09-28 12:34 PM there is a triplet of 458 in r1r3r5/c6. after that u get a 6 in r7c6. its plain solving after that Yes indeed. I could not spot that... | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | A general query guys....is it advisable to put more than 2 possible numbers in a box? Initially i was not in the habit of putting possible numbers in a box.In fact i hated that since i felt it made the whole sudoku very clustered.But i have realised that it is impossible to solve sudokus of greater difficulty without making a note of the possible numbers that occur in a box.But still is it advisable to write 3-4 numbers in a box and try to solve it if u get stuck, or to just write numbers where you get only 2 after eliminating the rest..This is something which i had always wanted to know from others because even after putting 2, i have got stuck in many a sudoku and the whole thing gets clear only when i put 3 numbers ...want to be sure that sudokus can be solved without writing more than 2 possible numbers in the box....ideas are welcome... | ||
prasanna16391 |
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2021 World Sudoku+Puzzle Convention Organizer Posts: 1801 Location: India | Its about the method that suits you best. Personally, I don't like using pencil marks at all. I do better on sites without pencil marks, and I try but I can't stop myself from using them subconsciously when they are there as a part of the interface(been trying to). I've talked to others though and the normal thing is to note down numbers to keep track. So I suppose you'll find this way easier. The difficult ones need a lot of pencil marks, because to add difficult tricks, the creator would have to use a larger group of numbers in the grid and solving them requires an understanding of that entire group. So there's nothing wrong in entering 4-5 pencil marks in a cell as long as you don't end up confusing yourself(which is my problem and why I'm faster without that). Edited by prasanna16391 2012-09-28 3:58 PM | ||
akash.doulani |
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SM 2020 (Math) Author Posts: 157 Location: India | @ kishore : from where do you get those sudokus ? they are pretty interesting to solve. can you share the source ? | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | I take them from fed sudoku...choose puzzle blogs from LMI home screen -->Fedsudoku--->sudoku archive--->classic printable.... They are my daily dosage of tablets for improving sudoku skills. | ||
prasanna16391 |
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2021 World Sudoku+Puzzle Convention Organizer Posts: 1801 Location: India | kishy72 - 2012-09-28 10:56 PM I take them from fed sudoku...choose puzzle blogs from LMI home screen -->Fedsudoku--->sudoku archive--->classic printable.... They are my daily dosage of tablets for improving sudoku skills. Akash is a regular there, he's just not been able to do them lately so didn't know I suppose. Anyway, I'm a regular there too. There's other sites as well with daily sudokus like Sudokucup, mindoku. These 3 are my daily routine anyway. Related to your earlier pencil marks question, mindoku's interface doesn't have pencil marks. | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | the way please in this Edited by kishy72 2012-10-06 9:57 PM | ||
kishy72 |
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SM 2020 (Math) Author Posts: 419 Location: India | oh my !!!! | ||
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Location: India | Just by going the marks you have done (and assuming that they are correct), where do you put 3 in Box2? However, I think you have gone wrong somewhere. I couldn't resolve the bottom 3 rows so early in the solve. | ||
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