7X7 — July Sudoku Test — 12-14 July | |
LMI Tests -> Monthly Sudoku and Puzzle Tests | 72 posts • Page 2 of 3 • 1 2 3 |
lenzo |
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Posts: 22 Location: ITALY | i hope the next test will be solvable online, since i don't have a printer here and i don't like to solve on paper and then submit, so i'll wait. | ||||||||||||||||||
Richard |
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WCPN Author Posts: 191 Location: The Netherlands | sbeck - 2014-07-14 9:34 PM I didn't get to the test in time. Can we get the password or unlock the PDF if we want to work on it offline? Thanks. The test is running till the end of today if you still want to participate. After that the password will be removed so you can solve in your own pace without the competition pressure. | ||||||||||||||||||
Para |
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Posts: 315 Location: The Netherlands |
Thanks Richard, that was fun. I had the most trouble with the Arrow, Consecutive Circles and Fortress, but I'm glad to be able to squeeze out all 20 in the last few seconds. I had a small issue with the diagonal Sudoku that it didn't print the dotted diagonal lines. It didn't really cause an issue as I checked the rules and added them myself. I don't know if anyone else had this issue. | ||||||||||||||||||
tamz29 |
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Posts: 225 Location: Thailand | It was a fun test. I admire how you can pull off so many nice tricks in such small grids. | ||||||||||||||||||
Niranjana Joshi |
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Posts: 3 | forgot the password .what to do? | ||||||||||||||||||
Richard |
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WCPN Author Posts: 191 Location: The Netherlands | Niranjana Joshi - 2014-07-15 2:06 AM forgot the password .what to do? It is in red letters on the submission page after you have clicked the start test-button. | ||||||||||||||||||
B. Thananon |
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Posts: 12 Location: Thailand |
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wiiwierdo |
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Posts: 2 Location: United Kingdom |
For my first test (and really my first proper experience with Sudoku as a whole) I obviously found this pretty challenging, but I really enjoyed the time I spent on it, and found the solving process was rather quick once I figured it out. Thanks for a great test! | ||||||||||||||||||
yureklis |
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CTC & TVC Author & Organizer Posts: 183 Location: Turkey |
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Richard |
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WCPN Author Posts: 191 Location: The Netherlands | 7x7 is now over. Congratulations to deu, TiiT and Nikola for the top positions. My guess was that the fastest player would need around 90 minutes or a bit less, so for that reason I set the duration at 100 minutes. I was already positive surprised when TiiT solved the whole set in 82 minutes on saturday but when I noticed deu's total time of 71 minutes early sunday morning, I almost fell of my chair. Really an incredible performance! Very, very well done!!! Players have given some feedback in the last days and I will respond to that in detail tomorrow. I will also write some notes to some puzzles as well as hints for some of the puzzles to get started. But that will be also tomorrow; I don't have enough time for that today. For now I thank all participants for taking part and LMI for giving me again the opportunity to write and present a sudoku test! Richard | ||||||||||||||||||
SKnight |
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Posts: 25 Location: United States |
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rakesh_rai |
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Mean Minis (2020) Author Posts: 774 Location: India | Richard for a very enjoyable test. | ||||||||||||||||||
achan1058 |
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Posts: 80 Location: Canada |
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rakesh_rai |
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Mean Minis (2020) Author Posts: 774 Location: India |
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Richard |
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WCPN Author Posts: 191 Location: The Netherlands | bob - 2014-07-13 6:47 AM Excellent quality puzzles, but very hard. Good for vacation. I miss Me. Stolk's puzzles in Breinbrekers. Maybe someday Puzzelsport will accept credit cards and I could subscribe in the USA. Thanks Bob! I wish you a lot of holidays with lots of puzzle fun! FYI: Breinbrekers doesn't exist anymore. It is taken off the market by the end of 2013. After that the Dutch Puzzle Association was erected. (Website: www.wcpn.nl) where you can solve a Breinbreker-like puzzle daily. If you are interested in my puzzles, check out the forum post about my Sudoku Variants Series or my author's profile about my friday-noon-puzzles, both on the website of Logic Masters Germany, where I am active for about 5/6 years now. An LMI player - 2014-07-14 4:27 AM Please make the puzzles larger! I have choosen exactly the same cell-size as in my previous tests; there were no complaints back then. Maybe it is an optical effect because there are now four puzzles on each page? At least writing space should be the same. tamz29 - 2014-07-14 10:48 PM It was a fun test. I admire how you can pull off so many nice tricks in such small grids. Thanks Tawan! I think you have made an interesting point here. Writing puzzles starts with a lot of thinking for me. (Especially for tests or championships.) On the way back in my car from work to home I tend to do a lot of thinking about puzzles. In the weeks before I actually start writing the puzzles, numerous ideas have crossed my mind about what 'tricks' I can apply. I like to explore the possibilities a variant offers. Especially for this 7x7-test I can add that it wasn't always easy to use my ideas. The fact that you have only seven digits and not much room makes it harder (than I thought), so quite some ideas didn't lead to a puzzle. I also used much more T&E to get there, so to say. Constructing 9x9-puzzles is easier. swaroop2011 - 2014-07-14 8:27 AM The puzzles were very nice, after solving one or two i felt they were tricky than hard. So needed more time to figure out in each. Thanks Swaroop. Your notes have made me think, and what I have written as response to Tawan's lines comes into sight here. (My) thinking about puzzles mostly concentrates on a) the opening or b) a by-pass in the solving route that can make a huge difference in solving times between top players and the rest of the field. I think you can call these solving steps indeed 'tricky', and I like to distinguish this from 'hard'. By putting these 'tricks' in my puzzles, I also hope that people learn something while solving my puzzles, so in the end I have contributed a small piece in the development of the puzzle sport. The notes to the puzzles that I will write in the next forum thread will be helpful if players didn't recognize the tricks during solving. | ||||||||||||||||||
Richard |
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WCPN Author Posts: 191 Location: The Netherlands | As promised yesterday, here are some notes to a selection of the puzzles in the set. I didn't re-read to check typos, so if you find one: just let me know! I hope these hints are helpful and I like to read feedback to confirm the intended route through the puzzle, or to report a shortcut that I missed... Law of leftovers For most of the players this will be a very trivial rule, but for those with not so much experience in solving irregular grids I will write a few lines about this. Law of leftovers is a rule that works in all irregular sudokus and it means that an area of ‘N’ rows or columns needs ‘N’ irregular areas. Looking to the first puzzle in the test: Rows 1, 2 and 3 contain two full irregular areas (top right and top middle) and one area that is ‘sticking out’ of those three rows; The F-shape top left has two cells sticking out of rows 1,2,3. At the same time, rows 1,2,3 have two cells ‘sticking in’; these are the cells in R3C5 and R3C7. The cells sticking into rows 1,2,3 must be the same as the cells sticking out of the area. The same rule works also for scattered grids. Looking to puzzle 3 in the booklet, there are three grey cells in rows 1 and 2. There are also three cells ‘sticking out’ of the first three rows, namely R4C123. Those cells sticking out contain the same digits as the three grey cells in rows 1 and 2. The fun part with scattered sudokus is that this works horizontally and vertically; The digits in R1C7 + R2C6 stick out of rows 1,2 and 3 as well as out of columns 5,6 and 7. Scattered I noticed some players had trouble with this puzzle from the basics page. There is a nice shortcut in the puzzle that some of you might have missed. 2 in R3 goes in R3C6; R7C6 = 2. R6C4 = 7; R4C6 = 5; R1C7 = 7; all 7’s; R2C4 = 5; R12C5 = {34}. R1C6 + R2C7 = {16}. This means that the grey cell in R2C6 can only be 3. Now the puzzle runs smooth. Quad Sums R7C1=4; R1C7 = 4 QS in R12C12 = 1+2+3=6; R34C1 = {57} 2 in R2 in C12; 3 in C1 in R12 QS in R67C67 = 1+2+3=6; R45C7 = {57} 2 in C7 in R67; 3 in R6 in C67 3 cannot go in R6C6 because of QS in R56C56. R6C7 = 3; R7C7 = 2 6 cannot go in R6C6. R6C6 = 1; R7C6 =6 R56C1 = {26} R2C2 = 2; R1C2 = 6 R23C7 = {16}; R1C1 = 1; R2C1 = 3 2 in shape in R56C4. Since 2 in C1 is in R56, QS R56C56 cannot contain 2. R5C5 = 1, R6C6 = 6. R5C1 = 6; R6C1 = 2; R5C4 = 2; R4C6 = 2; R3C5 = 2 Only place for 6 in R4 = R4C3; R4C4 = 1; R5C3 = 3 Toroidal Kropki One quick opening can be found in row 5. There are 3 white dots ‘covering’ 6 different cells, between C1 and C2; C4 and C5; C6 and C7. This means that the digit in R5C3 must be odd. Since there are a black and a white dot on both sides of this cell, that digit can only be 3. Consecutive Pair {24} in R2C4 + R4C2. R2 contains 2 dots which must have pairs {12} and {45} R2C13 = {67}; R13C2 = {15} The dot between R67C2 must have odd digit 7, which goes in R7C2; R6C2 = 6, R6C3 = 5. 5 in R4C6. Consecutive pair in R2C67 = {12}; R2C4 = 4; R2C5 = 5 OddMax 7 locked in R7C56; R5C3 = 7; R6C2 = 7 7 in C1 locked in R234; 7 in C7 locked in R123; 7 in R1 locked in C567. :=> R1C7 = 7 R2C5 = 7, R7C6 = 7, R3C4 = 7; R4C1 = 7 2 locked in R1C234; R3C6 = 2 5 in C6 in R6; 5 in C5 in R7; all 5’s 3 in shape in R5C6; 3 in shape in R67C3; R3C2 = 3; R1C5 = 3 Point to next R2C7 = 7; R2C6 = 6; R1C4 = 6; R2C5 = 1; R2C4 = 5 R6C3 = 6; R6C5 = 7 Palindrome A shortcut in the puzzle could be that the digit in R3C3 must be the same as in R5C5 and thus in R4C4 too. Equal A shortcut in this puzzle could be that the shape in the middle contains 5 digits; The number of odd digits must be even, so the number of even digits is odd, in a grid of 7x7 all even digits are included. Only possible combination is 2,4,6 + 5,7. Consecutive Circles Every circle must contain a 4! Law of leftovers: R13C3 = R7C45; R57C5 = R1C34 R1C4 = 3; R3C3 = 3; R5C5 = 2; R7C4 = 2 Center circle does not contain 2 and 3 so must be 4-5-6-7. R4C4 = 1. Bottom circle has {23} in R6C67; 4 in R7C67; 4 in R56C2; 4 in R12C1. 2 in U-shape left locked in R4C12; 2 in U-shape right locked in R23C7 R6C6 = 2; R6C7 = 3; R7C7 = 4 R4C6 = 3; R5C1 = 3; R2C2 = 3; R2C1 = 4; R1C2 = 6; R1C1 = 5 R23C6 = {56}; R7C6 = 1; R1C6 = 4; R5C6 = 7 R2C7 = 2; R56C2 = {14} 4 in R3 locked in C45 :=> R4C5 <>4 :=> 4 in C5 in R3C5 and 4 in R4C3. R4C5 = 6; R5C4 = 5; R3C4 = 7 Killer Counting of cages in rows 1/2; 6/7; columns 1/2; 6/7 leads to information on the sum of the three cells in those rows/columns that are not included in the cages. R1C1 + R2C12 have a sum of 6; R3C2 = 4 R6C67 + R7C7 have a sum of 11; R5C6 = 1 R67C7 have a sum of 11, combination of {47} or {56} R6C6 + R7C67 have a sum of 14. R7C6 is three higher than R6C7. R6C7 = 4; R7C6 = 7; R5C7 = 7 R6C6 + R7C7 = {25}; R67C5 = {36} 4 locked in R7C34; R4C1 = 4 7 locked in R1C45; R2C3 = 7; R1C23 = {56} 4 in C3 in R7C3 4 locked in R2C45; R1C6 = 4; R1C7 = 3; R2C67 = {56} Cage in R34C67 = {1236}; R3C5 = 5 1 locked in R6C34; cage [19] is {1567} R5C1 + R7C4 = {23} R2C1 + R5C1 form a pair on {23}; R1C1 = 1; R7C2 = 1 5 locked in R67C1 Cage [15] in R45C12 cannot contain 5. R1C2 = 5; R2C1 = 2 Low R6C5 = 1; R3C5 = 2; R3C3 = 1; R3C2 = 3; R24C2 = {12} R2C5 = 7; R2C1 = 6; R1C3 = 7; R4C4 = 7. R5C7 = 1; R7C4 = 1; R1C1 = 1; R2C6 = 1; R4C2 = 1; R2C2 = 2. R5C4 = 2; R1C6 = 2; R4C1 = 2; R7C3 = 2. 3 locked in R12C4; R6C3 = 3; R6C1 = 4; R7C1 = 3; all 3’s 4 locked in R57C2; R1C2 = 5; R2C3 = 4; R2C7 = 5 Sum 100 So far, I have seen only sum 100 sudokus in normal 9x9-grids; you can’t use all cells to be part of grey cell-combinations because of the total sum of 45. Therefore I deliberately wanted to create a puzzle where all cells of at least one row were included in sums, since the total sum of 28 can perfectly be split in 20 + 8(0); R1C146 have a sum of 8 and R1C2357 have a sum of 20. For R7 you can also determine the sums of 8 and 20 in the same way. Row 3 and 5 contain two sum-combinations. The digits in the left cells of these combinations add up to 9, the right cells add up to 10. R5C4 = 2. Now the combination of the digits in R5C1 + R5C5 can only by {45} since {36} would block both possibilities to build 10 in R5C2 + R5C6. So R5C1 = 4; R5C5 = 5. R5C26 = {37}; R5C37 = {16} Law of leftovers: R15C3 = R7C45. Since the 1 in the bottom row must be in the sum of 8 and thus in R7C136, 1 is not in R5C3. R5C3 = 6, R5C7 = 1. Law of leftovers: R45C7 = R3C15. R3C5 = 1. 1 must go in R1C4 (in both row and column it is the only place left). | ||||||||||||||||||
dkj |
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Posts: 1 Location: India |
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Bram28 |
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Posts: 35 Location: The Netherlands | Can the password please be removed? I didn't have a chance to compete in this contest, but still would like to solve the puzzles. Thanks! | ||||||||||||||||||
tnv |
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Posts: 22 Location: India | Will the scores in this test be included in the ratings | ||||||||||||||||||
Richard |
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WCPN Author Posts: 191 Location: The Netherlands | Bram28 - 2014-07-18 10:48 PM Can the password please be removed? I didn't have a chance to compete in this contest, but still would like to solve the puzzles. Thanks! It will be removed. For now: RS7x7=49 Have fun! | ||||||||||||||||||
Richard |
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WCPN Author Posts: 191 Location: The Netherlands | tnv - 2014-07-18 11:07 PM Will the scores in this test be included in the ratings Yes, but it may take some time before it is done. | ||||||||||||||||||
Bram28 |
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Posts: 35 Location: The Netherlands | Thanks Richard! They were fun. I do like the 7x7 format! | ||||||||||||||||||
vjain9 |
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Posts: 44 Location: India | Attempted the test . Just loved it ..... but now want to solve the puzzles at leisure - PW to the PUZZLE BOOKLET PLEASE ! | ||||||||||||||||||
Administrator |
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Location: India | vjain9 - 2014-07-24 10:33 AM Removed the password.Attempted the test . Just loved it ..... but now want to solve the puzzles at leisure - PW to the PUZZLE BOOKLET PLEASE ! | ||||||||||||||||||
vjain9 |
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Posts: 44 Location: India | thanks... Will try to go thru the Solving tips now | ||||||||||||||||||
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